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3 years ago

Solve for p(x) p(x)=(x^2+x+2)-[2x^2+2(-2x-4)]

Mathematics

1 answer:

Sliva [168]3 years ago

3 0

This question can be solved through trial and error method looking at the closest possibilities.

p(x)= (x^2 + x+2)- ( 2x^2 +2(-2x -4))

= (x^2 + x+2) - (2x^2 -4x -8) ( simplify inner brackets)

if x+2=0, x=(-2) ; p(x)= (-2)

( (-2)^2 + (-2)+2 ) - (2X(-2)^2 - 4X(-2) - 8) ( solve brackets using BODMAS rule)

(4+0) - (2X2 + 8-8)

4-4

= 0

therefore x= (-2)

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