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Roman55 [17]
2 years ago
12

5x5x5x5x6x7x8x8x9x9x9x9x9x9x10x12x13x14x15x16x17x18x19x20 WHAT DOES THIS EQUAL

Mathematics
2 answers:
Semenov [28]2 years ago
7 0
The answer your looking for is 5.441683e+23
trapecia [35]2 years ago
5 0

Answer:

5.441683e+23

Step-by-step explanation:

Hope it helped brainiest plz

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9 2/5-3 4/10<br> yo anyone have the answer
mamaluj [8]

Answer:

6

Step-by-step explanation:

9 and 2/5 is the equivilent to 9 and 4/10

9 4/10 - 3 4/10 = 6 0/10

5 0
2 years ago
Help me with this one pls
bagirrra123 [75]

1/3y + 28 = -5

Subtract 28 from both sides:

1/3y = -33

Multiply both sides by 3:

y = -99

The answer is E) NOTA

6 0
2 years ago
Read 2 more answers
8. Jonathan deposits $6,000 in a savings account that pays 3.2% interest compounded
Salsk061 [2.6K]

Answer:

About $6805.66 as I rounded it up

6 0
3 years ago
at the beginning of the school year Anderson Middle School had 480 students at the end of the year it had 504 students what is t
NikAS [45]

Answer:

The number of enrollments increased by 5%.

Step-by-step explanation:

Given that:

Number of students at the beginning of the year = 480

Number of students at the end of the year = 504

Change = 504 - 480 = 24

This indicates increase.

Percent of change = \frac{Change}{Old\ number\ of\ students}*100

Percent of change = \frac{24}{480}*100

Percent of change = 5%

Hence,

The number of enrollments increased by 5%.

4 0
2 years ago
If y varies directly as (x+3) and inversely as (x-3) and y=21 when x=4, what is the equation for y in terms of x?
igor_vitrenko [27]
\bf \qquad \qquad \textit{double proportional variation}&#10;\\\\&#10;\begin{array}{llll}&#10;\textit{\underline{y} varies directly with \underline{x}}\\&#10;\textit{and inversely with \underline{z}}&#10;\end{array}\implies y=\cfrac{kx}{z}\impliedby &#10;\begin{array}{llll}&#10;k=constant\ of\\&#10;\qquad  variation&#10;\end{array}\\\\&#10;-------------------------------\\\\

\bf \textit{\underline{y} varies directly as (x+3) and inversely as (x-3)}\implies y=\cfrac{k(x+3)}{x-3}&#10;\\\\\\&#10;\textit{we also know that }&#10;\begin{cases}&#10;y=21\\&#10;x=4&#10;\end{cases}\implies 21=\cfrac{k(4+3)}{4-3}\implies 21=\cfrac{k(7)}{1}&#10;\\\\\\&#10;\cfrac{21}{7}=k\implies 3=k\qquad thus\qquad \qquad \boxed{y=\cfrac{3(x+3)}{x-3}}
6 0
3 years ago
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