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ch4aika [34]
4 years ago
8

What is the range of the function on the graph

Mathematics
2 answers:
iragen [17]4 years ago
7 0

Answer:

all real numbers less than or equal to 3

Step-by-step explanation:

The range of the function is set of all y value for which the function is defined

To find out the range we look at the maximum or minimum point on the graph

Maximum point on the graph that is vertex is (-1,3)

x=-1 and y=3

The graph of y is below 3 (vertex)

So the range of the function is set of all real numbers less than or equal to 3

Dovator [93]4 years ago
6 0
Harizontile and diagniol because the line is going both ways
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MATH HELP PLEASE WILL GIVE BRAINLIEST!!!
Maurinko [17]
Hello,

When we have a quadrilateral inscribed in a circle, the opposite angles add up to 180 degrees (supplementary).

Therefore, we can write and solve the following equation first with angles B and D.
3x + 9 + 2x - 4 = 180
5x + 5 = 180
5x =175
x = 35

Then, sub 35 in the expression for angle A and you will get:
2(35) + 3
70 + 3
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Angle A is 73, that would make angle C equal to 107 degrees, because 180 - 73 = 107.

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MrEQ
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4 years ago
Please help this question I really cant get
Aleksandr [31]
Area = 78.54

Radius is 5
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6 0
3 years ago
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If a recipe called for 1/3 of a cup of flour how much flour would you need for 13 times the recipe?
charle [14.2K]
4.3 cups is how many cups of flour you need
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4 years ago
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The lesson is 19.2 Angles in inscribed Quadrilaterals
alexdok [17]

Answer:

m<R=44.9,m<S=56.9,m<T=44.9,m<U= 32.9.

Step-by-step explanation:

When two chords are equal then the measure of the arcs are equal.

Chord RU= Chord UT

Or , m arc RU= m arc UT,

3z-4=x+2z+7   Or             z=x+11

Chord RS=Chord ST ,

m arc RS=m arc ST=3x+5

Sum of m arc in a circle =360 degrees.

Or ,

3x+5+3x+5+3z-4+x+2z+7=360

7x+5z+13=360

Substituting z=x+11

7x+5(x+11)+13=360

7x+5x+55+13=360

12x+68=360

12x=292,x=24.3

z=x+11=11+24.3=34.3

m arc RU=marc UT= 3z-4=3(24.3)-4=69

m arc RS =marc ST= 3x+5=3(24..3)+5=77.9

m<R= (marc UT+ m  arc ST)÷2

m<R=(69+77.9)÷2=73.45

m<S= (m arc RU+m arc UT)÷2

m<S= (69+69)÷2=69

m<T=(m arc RU+m arc RS)÷2=73.45

m<U=(m arc RS+m arc m arc ST)÷2=77.9








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4 years ago
Find the circumcentre of the triangle whose vertices are 3,3 -4,-6 3.-6
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I think the answer is (-0.5, -1.5).
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