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nataly862011 [7]
4 years ago
6

foster is centering a photo that is 3 1/2 inches wide on a scrapbook page that is 12 inches wide. How far from each side of the

page should he put the picture?
Mathematics
1 answer:
Lady bird [3.3K]4 years ago
5 0
<span>The answer is that Foster should position the page so that the picture is 4.25 inches away from each side. We can reach this conclusion by first subtracting 3.5 from 12 to get 8.5 inches, and then divide this by 2 to get 4.25 inches.</span>
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If ABCD is dilated by a factor of 2, the
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(4,4) are the coordinates of C prime
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3 years ago
Tell whether the given value is a solution of the inequality.<br> x + 1 &gt; 10; x = 9
Oliga [24]

Answer:

given x+1 > 10,

x > 10 - 1

x > 9

which means x MUST BE more than 9 , which also means 9 isnt included in the inequality therefore x = 9 is not a solution.

6 0
3 years ago
The probability of an event - picking teams. About (a) 10 kids are randomly grouped into an A team with five kids and a B team w
LuckyWell [14K]

Answer: The required probability is \dfrac{4}{9}

Step-by-step explanation:

Since we have given that

Number of kids = 10

Number of kids in Team A = 5

Number of kids in Team B = 5

There are three kids in the group, Alex and his two best friends Jose and Carl.

So, number of favourable outcome is given by

2(\dfrac{8!}{3!\times 5!})

Total number of outcomes is given by

\dfrac{10!}{5!\times 5!}

So, the probability that Alex ends up on the same team with at least one of his two best friends is given by

\dfrac{2(\dfrac{8!}{5!\times 3!)}}{\dfrac{10!}{5!\times 5!}}\\\\=2\times \dfrac{8!}{3!}\times \dfrac{5!}{10!}\\\\=\dfrac{4}{9}

Hence, the required probability is \dfrac{4}{9}

3 0
3 years ago
A purchaser of electric relays buys from two suppliers, A and B. Supplier A supplies two of every three relays used by the compa
inessss [21]

Answer:

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409.

Step-by-step explanation:

We can model this question with a binomial distribution random variable.

The sample size is n=60.

The probability that the relay come from supplier A is p=2/3 for any relay.

If we use a normal aproximation, we have the mean and standard deviation:

\mu=np=60*(2/3)=40\\\\\sigma=\sqrt{npq}=\sqrt{60*(2/3)*(1/3)} =3.65

The probability that at most 38 of the 60 relays are from supplier A is P(X≤38)=0.3409:

P(X\leq38)=P(X

5 0
3 years ago
Slove the equation<br> 6x+4/5=8
Advocard [28]
6x+4/5=8 subtract 6x from both sides 4/5=8-6x multiply both sides by 5 to get rid of the fraction 4=40-30x divide both sides by 2 2=20-15x add 15x to both sides 15x+2=20 subtract 2 from both sides 15x=18 divide both sides by 15 x=1.2
3 0
3 years ago
Read 2 more answers
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