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AfilCa [17]
3 years ago
7

5.Solve:

Mathematics
1 answer:
lara31 [8.8K]3 years ago
8 0

Answer:

C) x=2 y=-1 z=3

Step-by-step explanation:

2x + y - z = 0

2(2) + (-1) - (3) = 0

0 = 0

x - y + z =6

2 - (-1) + 3 = 6

6 = 6

x + 2y + z = 3

2 + 2(-1) + 3 = 3

3 = 3

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4 0
3 years ago
Read 2 more answers
Please help ill give brainiest answer
trapecia [35]

Answer:

1: AAS, RQC 2: ASA, SRP

Step-by-step explanation:

(1) We are shown that two angles and one side are congruent in the order of AAS. Make sure you write the letters in terms of the corresponding angles. The angles and sides are congruent because the problem labels it for us. For example, B,A,C=R,Q,S. Answers: AAS, RQC.

(2) We are shown that two angles and one side are congruent in the order of ASA. Make sure you write the letters in terms of the corresponding angles again. For example, P,Q,R=P,S,R. The angles are congruent because the problem labels it for us. Side PR is congruent to side PR by reflexive property. Answers: ASA, SRP.

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4 0
3 years ago
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bearhunter [10]

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Step-by-step explanation:

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5 0
2 years ago
Solve for the positive value of x: 6x2 – 54 = 0
n200080 [17]
If you would like to solve for the positive value of x, you can do this using the following steps:

6 * x^2 - 54 = 0      /6
x^2 - 9 = 0
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4 0
3 years ago
For what values of x and y must ABCD be a parallelogram?
n200080 [17]
<h2>x^{\circ}=21^{\circ} \ and \ y^{\circ}=39^{\circ}</h2>

Step-by-step explanation:

We know that vertically opposite angles of a parallelogram are equal .

\angle ABC =\angle ADC\ and \ \angle BAD = \angle DAC

⇒3x^{\circ}=(4x-21)^{\circ} \ and \ 3y^{\circ}=(y+78)^{\circ}

⇒3x^{\circ}-4x^{\circ}=-21^{\circ} \ and \ 3y^{\circ}-y^{\circ}=78^{\circ}

⇒-x^{\circ}=-21^{\circ} \ and \ 2y^{\circ}=78^{\circ}

⇒x^{\circ}=21^{\circ} \ and \ y^{\circ}=39^{\circ}

7 0
3 years ago
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