14b + 6b - 12
(14b + 6b) - 12 collect like terms
20b - 12 << your answer
hope this helps, God bless!
The distance from the center of dilation, P, to.the image vertice S' is; 6 units.
<h3>What is the distance from the center of dilation, P, to the image S'?</h3>
It follows from the task content that the center of dilation of the triangle QRS is point P and the length of segment PS in the pre-image is; 8 units.
Hence, since the dilation factor as given in the task content is; three-fourths, it therefore follows that the distance of point P to S' in the image is; (3/4) × 8 = 6units.
Read more on dilation;
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Answer:
There is no variable so -3 therefore cannot be a solution to this.
We know the length and width. We're just trying to find all of the area in between. To find area, we do length*width. Length is 11.5 and the width is 10.75. 11.5*10.75=123.625 ft^2
Factor out the gcf
factor by grouping
perfect square trinomial
or
difference of squares
?
