Hi!
All of these can be represented as fractions:
1.) 4/12
2.) 15/27
3.) 12/18
4.) 9/72
Now, if they are supposed to be <em>simplified</em>...
1.) Divide 4 and 12 by 4, and you get 1/3
2.) Divide 15 and 27 by 3, and you get 5/9
3.) Divide 12 and 18 by 6, and you get 2/3
4.) Divide 9 and 72 by 9, and you get 1/8
Hope this helps! :D
Answer:
Step-by-step explanation:
![\displaystyle [POSITIVE, NEGATIVE] → QUADRANT\:IIII \\ [NEGATIVE, NEGATIVE] → QUADRANT\:III \\ [NEGATIVE, POSITIVE] → QUADRANT\:II \\ [POSITIVE, POSITIVE] → QUADRANT\:I](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5BPOSITIVE%2C%20NEGATIVE%5D%20%E2%86%92%20QUADRANT%5C%3AIIII%20%5C%5C%20%5BNEGATIVE%2C%20NEGATIVE%5D%20%E2%86%92%20QUADRANT%5C%3AIII%20%5C%5C%20%5BNEGATIVE%2C%20POSITIVE%5D%20%E2%86%92%20QUADRANT%5C%3AII%20%5C%5C%20%5BPOSITIVE%2C%20POSITIVE%5D%20%E2%86%92%20QUADRANT%5C%3AI)
I am joyous to assist you at any time.
First off, why is this in the mathematics section lol. Anyways, the essay looks good, but you can remove some unnecessary information. The reader doesn't need to know that the author is 14. Knowing the age of an author won't help support your argument.
Also, you say, "For example during the pandemic situation there were some quick changes to it like the vaccines being made...".
I would say instead, "During the pandemic, there were some rapid changes that took place to correct the pandemic like the vaccines being made...". Other than that, the essay looks good!
Answer:
Therefore, the total Resistance: R = 93.9 Ω
Step-by-step explanation:
Given
R₁ = 1 × 10²
R₂ = 2.5 kΩ = 2.5 × 10³ Ω
R₃ = 4 kΩ = 4 × 10³ Ω
Given that the given resisters are connected parallel, so using the formula to calculate the total Resistance R:
susbtituting R₁ = 1 × 10², R₂ = 2.5 × 10³ Ω, and R₃ = 4 × 10³ Ω
Multiply by LCM of R, 100, 2500, and 4000: 20000 R
simplify
Switch sides
Divide both sides by 213
Simplify
Ω
Therefore, the total Resistance: R = 93.9 Ω
