Answer:
c: v=5000(1.35)
Step-by-step explanation:
3.5 interest in point-slope decimal form is 1.35.
v=5000(1.35) is final answer
Answer:
482 km
63.94 degrees
Step-by-step explanation:
to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.
Cosine rule states that
C = ![\sqrt{A^{2} + B^{2} -2AB cos(c) }](https://tex.z-dn.net/?f=%5Csqrt%7BA%5E%7B2%7D%20%2B%20B%5E%7B2%7D%20-2AB%20%20%20cos%28c%29%20%20%7D)
where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060
solving now, we have
C = ![\sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60) }](https://tex.z-dn.net/?f=%5Csqrt%7B500%5E%7B2%7D%20%2B%20300%5E%7B2%7D%20-2%20%2A%20500%20%2A%20300%20cos%2860%29%20%20%7D)
C = ![\sqrt{250000 + 90000 - [215000 cos(60) }]](https://tex.z-dn.net/?f=%5Csqrt%7B250000%20%2B%2090000%20-%20%5B215000%20%20%20cos%2860%29%20%20%7D%5D)
C = ![\sqrt{340000 - [215000 * 0.5 }]](https://tex.z-dn.net/?f=%5Csqrt%7B340000%20-%20%5B215000%20%2A%200.5%20%20%7D%5D)
C = ![\sqrt{340000 - [107500 }]](https://tex.z-dn.net/?f=%5Csqrt%7B340000%20-%20%5B107500%20%20%7D%5D)
C =![\sqrt{232500}](https://tex.z-dn.net/?f=%5Csqrt%7B232500%7D)
C = 482 km
The bearing can be gotten by using the Sine Rule.
= ![\frac{sinc}{C}](https://tex.z-dn.net/?f=%5Cfrac%7Bsinc%7D%7BC%7D)
sina/500 = sin60/482
482 sina = 500 sin60
sina = ![\frac{500 sin60}{482}](https://tex.z-dn.net/?f=%5Cfrac%7B500%20sin60%7D%7B482%7D)
sina = 0.8983
a = sin^-1(0.8983)
a = 63.94 degrees
Answer:
You do 1/5 x 125 which equals 25
Step-by-step explanation:
Wow a lot of plants but make a Mendelson Square [looks like a tic- tac -toe board (# this super large) with p and w at the top and p and w down the side. I would some how get those numbers checked out cuz generally there are only 4 squares:)