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Gennadij [26K]
3 years ago
11

Here this to help the 7th graders A complete overveiw

Mathematics
2 answers:
spayn [35]3 years ago
7 0
Thank u so much ur the best >3
Ymorist [56]3 years ago
3 0

Answer: wow thank you

Step-by-step explanation:

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Ax-bx+y=z solve for x​
Vladimir [108]

Answer:

This question requires us to change the subject of a formula. This can be achieved by following the order of operations in reverse. First, isolate the terms with our variable of interest, x:

ax - bx = z - y

Then, we take x out as it is being multiplied to both a and b:

x(a - b) = z - y

Dividing (a - b) on both sides, we get:

x = (z - y) / (a - b)

Thus, the answer is x= z-y/a-b

Step-by-step explanation:

6 0
3 years ago
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Please and thank you
Hunter-Best [27]

Answer:

i thinks its B thats what i put but im not sure , i havent got the paper back yet

Step-by-step explanation:

8 0
3 years ago
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If a team scored 96 points while making 18 free throws, how many field goals were made?
vlabodo [156]

Answer:

26 free throws

Step-by-step explanation:

96-18=78

78 divided by how much one free throw is worth (3)

you would get 26

hope this helps!

8 0
3 years ago
If triangle BNV ~ triangle BRG, BR=4x+7 and BG= 18 find the value of x
Bingel [31]

Answer:

x=5

Step-by-step explanation:

5 0
3 years ago
Help please!!!!!!!!!
In-s [12.5K]

ANSWER

24


EXPLANATION

For a matrix A of order n×n, the cofactor C_{ij} of element a_{ij} is defined to be


   C_{ij} = (-1)^{i+j} M_{ij}


M_{ij} is the minor of element a_{ij} equal to the determinant of the matrix we get by taking matrix A and deleting row i and column j.


Here, we have


   C_{11} = (-1)^{1+1} M_{11} = M_{11}


M₁₁ is the determinant of the matrix that is matrix A with row 1 and column 1 removed. The bold entries are the row and the column we delete.


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right)  \end{aligned}


Since the determinant of a 2×2 matrix is


   \det\left(  \begin{bmatrix} a & b \\ c& d  \end{bmatrix} \right) = ad-bc


it follows that


   \begin{aligned} A=\begin{bmatrix} \bf 1 & \bf -6 & \bf -4\\ \bf 7 & 0 & -3 \\ \bf -9 & 8 & -8 \end{bmatrix} \implies M_{11} &= \text{det}\left(\begin{bmatrix} 0&-3 \\ 8&-8 \end{bmatrix} \right) \\ &= (0)(-8) - (-3)(8) \\ &= -(-24) \\ &= 24 \end{aligned}


so C_{11} = M_{11} = 24

4 0
3 years ago
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