Answer:
t = 4 seconds
Step-by-step explanation:
The height of the projectile after it is launched is given by the function :
t is time in seconds
We need to find after how many seconds will the projectile land back on the ground. When it land, h(t)=0
So,
The above is a quadratic equation. It can be solved by the formula as follows :
Here, a = -16, b = 32 and c = 128
Neglecting negative value, the projectile will land after 4 seconds.
Answer:
Two-tailed test.
Step-by-step explanation:
There are two types of tests:
One-tailed tests and two-tailed tests.
When we only test if the mean is less or more than a value, we have a one-tailed test.
When we test if the mean is different from a value, we have a two-tailed test.
If you were to conduct a test to determine whether there is evidence that the proportion is different from 0.30, which test would you use?
Test if it is different, so a two-tailed test.
Because it is the same by the 0 and the 0 represents as a place holder for the 32
Given that GI = 53, and
• GH = 3x - 11
• HI = 2x + 4
We can establish the following equality statement to solve for x:
GH + HI = GI
3x - 11 + 2x + 4 = 53
Combine like terms:
5x - 7 = 53
Add 7 to both sides:
5x - 7 + 7 = 53 + 7
5x = 60
Divide both sides by 5 to solve for x:
5x/5 = 60/5
x = 12
Substitute the value of x into the equality statement to verify if it is the correct value for x:
GH + HI = GI
3x - 11 + 2x + 4 = 53
3(12) - 11 + 2(12) + 4 = 53
36 - 11 + 24 + 4 = 53
53 = 53 (True statement. Thus, x = 12 is the correct value).
Therefore:
GH = 3x - 11
GH = 3(12) - 11
GH = 25
HI = 2x + 4
HI = 2(12) + 4
HI = 28
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