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2 years ago

5

Solve for homework :)

2 answers:

katrin2010 [14]2 years ago

6 0

Answer:

$1) \frac{ {a}^{8} }{ {a}^{6} } \\ = {a}^{8} \times {a}^{ - 6} = {a}^{2} \\ 2) {m}^{2} {m}^{ - 4} = {m}^{ - 2} \\ thank \: you$

Alex73 [517]2 years ago

3 0

Answer:

8. a^2

9. 1/m^2

Step-by-step explanation

8. Subtract the powers

9. Subtract the powers (2-4) and get m^-2, which is 1/m^2

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Will someone help me with this please

ANEK [815]

the first answer choice, associative property of addition

hope this helps. gl!

8 0

3 years ago

Read 2 more answers

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

T-shirts are sold in packages of 4.The store’s 139 employees will each be given 5 t-shirts. How many packages will the store nee

Novosadov [1.4K]

Answer:

174 packages of t-shirts PLEASE GIVE BRAINLIEST

Step-by-step explanation:

139 x 5 = 695 t-shirts are needed

695 ÷ 4 = 173.75

Since you have to purchase whole packages of t-shirts you will need to buy 174 packages of t-shirts. 174 x 4 = 696 t-shirts

174 packages

8 0

3 years ago

Evaluate the function for f(3).<br> f(x) = -3x - 8

scoundrel [369]

If 3 is x that means y is -17 so that mean f=-17/3

8 0

3 years ago

D all the time and I like the time you

andriy [413]

Answer:

Step-by-step explanation:

1a+1b(a+b-c)+1b+1c(b=c-a)+ 1a+1c(c+a-b)

1a+1b-c+1b +1c-a+1a+1c-b

1a+2b-c+a+1c-b

2a+1b+c this is the answer I think lol

6 0

2 years ago