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Charra [1.4K]
3 years ago
14

A textbook weighs 2.5 pounds. How many kilograms does the textbook weigh? Round your answer to the nearest tenth of a pound. 1 k

g ≈ 2.2 lb
Mathematics
1 answer:
Alenkasestr [34]3 years ago
4 0
The solution to the problem is as follows:

Given: 2.5 lb

Asked: 2.5 lb -----> kg

Answer:

2.5 lb * ( 1 kg/2.2 lb) = 1.1 kg

Therefore, the weight of the book in kg is 1.1 kg.

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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A stack of one hundred fifty cards is placed next to a ruler, and the height of the stack is measured to be 5/8 inches.
DaniilM [7]
Divide 5/8 by 150, to see how thick each is, that'll give you 150 even pieces that add up to 5/8

\bf \cfrac{\frac{5}{8}}{150}\implies \cfrac{\frac{5}{8}}{\frac{150}{1}}\implies \cfrac{5}{8}\cdot \cfrac{1}{150}\implies \cfrac{1}{8\cdot 30}\implies \cfrac{1}{240}
5 0
3 years ago
Suppose 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea. Use a 0.05 significance
lana66690 [7]

Answer:

Null Hypothesis, H_0 : p = 0.20  

Alternate Hypothesis, H_a : p > 0.20  

Step-by-step explanation:

We are given that 241 subjects are treated with a drug that is used to treat pain and 54 of them developed nausea.

We have to use a 0.05 significance level to test the claim that more than 20​% of users develop nausea.

<em>Let p = population proportion of users who develop nausea</em>

So, <u>Null Hypothesis,</u> H_0 : p = 0.20  

<u>Alternate Hypothesis</u>, H_a : p > 0.20  

Here, <u><em>null hypothesis</em></u> states that 20​% of users develop nausea.

And <u><em>alternate hypothesis</em></u> states that more than 20​% of users develop nausea.

The test statistics that would be used here is <u>One-sample z proportion</u> test statistics.

                     T.S. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }   ~ N(0,1)

where,  \hat p = proportion of users who develop nausea in a sample of 241 subjects =  \frac{54}{241}  

             n = sample of subjects = 241

So, the above hypothesis would be appropriate to conduct the test.

6 0
3 years ago
Julia can finish a 20-mile bike ride in 1.2 hours. Katie can finish the same bike ride in 1.6 hours. To the nearest tenth of a m
Brums [2.3K]

Answer:

Step-by-step explanation:

julia : 20 miles in 1.2 hrs = (20/1.2) = 16.67 miles per hr

katie : 20 miles in 1.6 hrs = (20 / 1.6) = 12.5 miles per hr

how much faster does julia ride then katie...

16.67 - 12.5 = 4.17 rounds to 4.2 miles per hr faster <==

4 0
3 years ago
Officer Brimberry wrote 32 tickets for traffic violations last week, but only 12 tickets this week. What is the percent decrease
kolbaska11 [484]

Answer:

62.5 %

Step-by-step explanation:

you have to subtract 32-12, which equals 20

then divide 20 by the original amount (20/32)

20/32= .625, then you have to multiply to get the final answer...hope this helped!

4 0
2 years ago
The Academic Computing Center has five trainers available in its computer labs to provide training sessions to students. Assume
kondor19780726 [428]

Answer:

87.72%

Step-by-step explanation:

Data provided in the question:

Design capacity of the system = 1900 students per semester

Effective capacity = 90% of design capacity

Actual number of students = 1500

Now,

Efficiency = [ [ Actual capacity ] ÷ [ Effective capacity ] ] × 100%

also,

Effective capacity = 90% of 1900

= 0.90 × 1900

= 1710

Efficiency = [ 1500 ÷ 1710 ] × 100%

= 0.8772 × 100%

= 87.72%

7 0
3 years ago
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