Answer:
Step-by-step explanation:
A. It is an experiment as the sales director is applying treatment to a group and recording the results.
B. I would have two hundred fifty sales representatives from each region take the training and two hundred fifty from each region to not take it so i can be able to see if it affects both regions differently. The representatives from each region would be chosen at random and the length of their training would be the same for all.
C. now you would only be able to have 200 people from each region train. this would lower the percentage of the impact the training had on the amount of sales.Ex, if the original 250 trained people in a region increased the sales in that region by 20% and 50 of those people ended up not actually training, the sales would have only went up by 16%.
D. cor relational research is best to establish causality.Ex, the amount of training the representatives got may affect how much they are able to sell. also the number of representatives trained may affect the amount sold
4300×.30 = 1290
Her costs should be no more than $1290
A) maximum mean weight of passengers = <span>load limit ÷ number of passengers
</span><span>
maximum mean weight of passengers = 3750 </span>÷ 25 = <span>150lb
</span>B) First, find the z-score:
z = (value - mean) / stdev
= (150 - 199) / 41
= -1.20
We need to find P(z > -1.20) = 1 - P(z < -1.20)
Now, look at a standard normal table to find <span>P(z < -1.20) = 0.11507, therefore:
</span>P(z > -1.20) = 1 - <span>0.11507 = 0.8849
Hence, <span>the probability that the mean weight of 25 randomly selected skiers exceeds 150lb is about 88.5%</span> </span>
C) With only 20 passengers, the new maximum mean weight of passengers = 3750 ÷ 20 = <span>187.5lb
Let's repeat the steps of point B)
z = (187.5 - 199) / 41
= -0.29
P(z > -0.29) = 1 - P(z < -0.29) = 1 - 0.3859 = 0.6141
</span>Hence, <span>the probability that the mean weight of 20 randomly selected skiers exceeds 187.5lb is about 61.4%
D) The mean weight of skiers is 199lb, therefore:
number</span> of passengers = <span>load limit ÷ <span>mean weight of passengers
= 3750 </span></span><span>÷ 199
= 18.8
The new capacity of 20 skiers is safer than 25 skiers, but we cannot consider it safe enough, since the maximum capacity should be of 18 skiers.</span>
