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SIZIF [17.4K]
3 years ago
13

The greatest ocean depths on the earth are found in the marianas trench near the philippines, where the depth of the bottom of t

he trench is about 11.0 km. calculate the pressure due to the ocean at a depth of 9.1 km, assuming seawater density is constant all the way down. (the validity of the assumption of constant density is examined in one of the integrated concept problems.)
Physics
1 answer:
Doss [256]3 years ago
3 0
To find the pressure with a given data for the height, you are asked to get the hydraulic pressure. Hydraulic pressure has the following formula:

P = density*acceleration due to gravity*height

Assume that the density of seawater is the same as that for pure water,density = 1000 kg/m^3.

P = 1000 kg/m3*9.81m/s2*9100m
P = 89271000 Pascals or 89.271 megapascals
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An air track car with a mass of 0.75 kg and a velocity of 8.5 m/s to the right collides elastically with a 0.65kg car moving to
Sunny_sXe [5.5K]
We can do this with the conservation of momentum. The fact it is elastic means no KE is lost so we don't have to worry about the loss due to sound energy etc.

Firstly, let's calculate the momentum of both objects using p=mv:

Object 1:
p = 0.75 x 8.5 = 6.375 kgm/s

Object 2 (we will make this one negative as it is travelling in the opposite direction):
p = 0.65 x -(7.2) = -4.68 kgm/s

Based on this we know that the momentum is going to be in the direction of object one, and will be 6.375-4.68=1.695 kgm/s

Substituting this into p=mv again:

1.695 = (0.75+0.65) x v
Note I assume here the objects stick together, it doesn't specify - it should!

1.695 = 1.4v
v=1.695/1.4 = 1.2 m/s to the right (to 2sf)
8 0
3 years ago
Hydrostatic pressure is deadly to sea creatures true or false
Doss [256]

It is to some sea creatures. Like the ones with air filled areas like lungs and swim bladders

4 0
4 years ago
Read 2 more answers
How far away are the Stars?
Shtirlitz [24]

Answer:

25,300,000,000,000 miles away

8 0
3 years ago
I need help, what are the steps to solve this , I don’t understand
Xelga [282]
It is slightly above 48 degrees celsius, so try 48.2 degrees celsius. If that doesn’t work try 48.1 degrees celsius.
4 0
2 years ago
Light with a wavelength of λ = 689 nm. is incident on a single slit of width w = 3.75 micrometers. A screen is located L = 0.65
rodikova [14]

Answer:

119.42 x 10⁻³ m

Explanation:

The distance of first dark fringe from central bright spot will be equal to the width of fringe .

Fringe width = λL /w

where λ is wavelength of light, w is slit width , L is distance of screen .

So required distance

= \frac{689\times10^{-9}\times0.65}{3.75\times10^{-6}}

= 119.42 x 10⁻³ m

8 0
3 years ago
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