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Alecsey [184]
3 years ago
13

Help with question 16 and 17

Physics
1 answer:
storchak [24]3 years ago
5 0
<h3>16.</h3>

Your answer is correct.

___

<h3>17.</h3>

The fractional change in resistance is equal to the given temperature coefficient multiplied by the change in temperature.

  R = R₀×(1 + α×ΔT)

  R = (10.0 Ω)×(1 + 0.004×(65 -20)) = 11.8 Ω

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Fill in the blank below: In a _______________ digestive system, digestion takes place outside of the cells in a series of tubes.
Elina [12.6K]

Answer : Option D) Complete.

Explanation : In a complete digestive system, digestion takes place outside of the cells in a series of tubes. Food enters through one opening and food remnants exit out of a different opening. It has examples of humans, dogs, horses, spiders and earthworms. This system is complete because it does not occurs inside a cell nor it occurs in sponge kind-off organs and it is also not incomplete digestion as the waste products are removed from the other opening.

Therefore, the correct answer is option D) complete.

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smooth , hard , round
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During a rockslide, a 670 kg rock slides from rest down a hillside that is 740 m along the slope and 240 m high. The coefficient
ElenaW [278]

a) 1.58\cdot 10^6 J

b) 1.15\cdot 10^6 J

c) 0.43\cdot 10^6 J

d) 35.8 m/s

Explanation:

a)

The gravitational potential energy of an object is the energy possessed by the object due to its location with respect to the ground.

It is given by:

U=mgh

where

m is the mass of the object

g is the acceleration due to gravity

h is the height of the object, relative to a reference level

Here, the reference level is taken at the bottom of the hill (where the potential energy is zero).

So, we have:

m = 670 kg is the mass of the rock

g=9.8 m/s^2

h = 240 m is the initial height of the rock

So, the potential energy of the rock just before the slide is

U=(670)(9.8)(240)=1.58\cdot 10^6 J

b)

The energy transferred to thermal energy during the slide is equal to the work done by friction, which is:

W=F_f d

where

F_f is the force of friction

d = 740 m is the displacement of the rock along the ramp

The force of friction is given by:

F_f=-\mu mg cos \theta

where

\mu=0.25 is the coefficient of friction

m = 670 kg is the mass of the rock

\theta is the angle of the ramp

Since we know the lenght of the ramp (d = 740 m) and the height (h = 240 m), we can find the angle:

\theta=sin^{-1}(\frac{h}{d})=sin^{-1}(\frac{240}{740})=18.9^{\circ}

Therefore, the work done by friction is:

W=-\mu m g cos \theta d =-(0.25)(670)(9.8)(cos 18.9^{\circ})(740)=-1.15\cdot 10^6 J

So, the energy transferred to thermal energy is 1.15\cdot 10^6 J.

c)

According to the law of conservation of energy, the kinetic energy of the rock as it reaches the bottom of the hill will be equal to the initial potential energy (at the top) minus the energy transformed into thermal energy.

Therefore, we have:

K_f = U_i -E_t

where here we have:

U_i=1.58\cdot 10^6 J is the potential energy of the rock at the top of the hill

E_t=1.15\cdot 10^6 J is the energy converted into thermal energy

Substituting, we find

K_f=1.58\cdot 10^6-1.15\cdot 10^6=0.43\cdot 10^6 J

So, this is the kinetic energy of the rock at the bottom of the hill.

d)

The kinetic energy of the rock at the bottom of the hill can be rewritten as

K_f=\frac{1}{2}mv^2

where

m is the mass of the rock

v is its final speed

In this problem, we have:

K_f=0.43\cdot 10^6 J is the final kinetic energy of the hill

m = 670 kg is the mass of the rock

Therefore, the final speed of the rock is:

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(0.43\cdot 10^6)}{670}}=35.8 m/s

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Could a car drive on a frictionless surface? Explain using the terms action
Julli [10]

Answer:

No, it cannot. The car needs the friction of the surface to drive because the car pushes the surface backwards, and the surfaces makes a reaction force pushing the car forward, and that works because of the friction. In a frictionless surface the tires would rotate in the same place

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What does the term homeostasis mean?
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Answer:

Homeostasis: A property of cells, tissues, and organisms that allows the maintenance and regulation of the stability and constancy needed to function properly. Homeostasis is a healthy state that is maintained by the constant adjustment of biochemical and physiological pathways.

Explanation:

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