Step-by-step explanation:
The answer is OPTION C
Find the Inverse of a 3x3 Matrix.
First
Find the Determinant of A(The coefficients of e
Proceed towards finding the CO FACTOR of the 3x3 Matrix.
+. - +
A= [ 1 -1 -1 ]
[ -1 2 3 ]
[ 1 1 4 ]
The determinant of this is 1.
Find the co factor
| 2 3 | |-1 3 | |-1 2 |
| 1. 4. | |1 4 | |1. 1 |
|-1. -1 | |1 -1 | |1 -1
| 1. 4 | |1. 4| |1 1|
|-1. -1 | |1 -1 | |1. -1
|2. 3| |-1. 3| |-1 2|
After Evaluating The Determinant of each 2x 2 Matrix
You'll have
[ 5 7 -3]
[3 5 -2 ]
[-1 -2 1]
Reflect this along the diagonal( Keep 5,5 -2)
Then switching positions of other value
No need of Multiplying by the determinant because its value is 1 from calculation.
After this
Our Inverse Matrix Would be
[ 5 3 -1 ]
[7 5 -2 ]
[ -3 -2 1]
THIS IS OUR INVERSE.
SO
OPTION C
Answer:
900
Step-by-step explanation:
Margin of error = critical value × standard error
The margin of error is given to be 0.05.
At 99.5% confidence, the critical value is z = 3.
The standard error for a proportion is √(pq/n). Since p is not given, we will assume p = 0.5.
0.05 = 3 √(0.5 × 0.5 / n)
n = 900
Answer:
(x + 2) (x + 3)
Step-by-step explanation:
x² + 5x + 6
x² + 3x + 2x +6
Answer:
A. The first graph
Step-by-step explanation:
When you graph these two equations on a graphing calc, you should be able to see one dotted line and one solid, as well as the solutions being mostly in the 1st quadrant.
Answer:
16,460 gallons
Step-by-step explanation:
This is a differential equation problem, we have a constant flow of contaminant into the lake, but also we know that only a fraction of that quantity of contaminant remains because of the enzymes. For that reason, the differential equation of contaminant's flow into the lake would be:
Then, we have to integrate in order to find the equation for Q(t), as the quantity of contaminant in the lake, in function of time.
Now, we use the given conditions to replace them in the equation, in order to solve for 
Then, we reorganize the equation and we replace t for 17 hours, in order to determine the quantity of contaminant at that time:
