F(x)= x² + 5, is just a parabola shfited upwards by 5 units, so, is a smooth graph and no abrupt edges, so from 0 to 3, is indeed differentiable and continuous. So Rolle's theorem applies, let's check for "c" by simply setting its variable to 0, bear in mind that, looking for "c" in this context, is really just looking for a critical point, since we're just looking where f'(c) = 0, and is a horizontal tangent line.
Answer:
$255
Step-by-step explanation:
250*.85=212.5
212.5*1.2=255
Factors of 30: 1,2,3,5,6,10,15,30
X = 3
2(4x - 3) - 8 = 4 + 2x
1. Distribute
8x - 6 - 8 = 4 + 2x
2. Collect like terms
8x - 14 = 4 + 2x
3. Collect like terms again (add 14 and subtract 2x)
6x = 18
4. Divide by 6
x = 3