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Olin [163]
3 years ago
10

How to solve -2(x+3)=8​

Mathematics
2 answers:
Shtirlitz [24]3 years ago
5 0
-2(x + 3) = 8

Multiply -2 with x and 3

-2x -6 = 8

Now add 6 to both sides

-2x -6 = 8
+6 +8

-2x = 16

Lastly divide -2 from both sides to find x


-2x = 16
—— —-
-2x -2x


X = -8
Art [367]3 years ago
4 0

Answer:

x=-7

Step-by-step explanation:

-2(x+3)=8

-2x-6=8

-2x=8+6

-2x=14 -2x/-2=14/-2

x= -7

if you want to be sure do the following

-2(-7+3)=8

-2(-4)=8

8=8

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Answer:

Step 1 is ya answer!!! UwU

Step-by-step explanation:

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4 0
3 years ago
What is the answer to x-2=7
saul85 [17]

x-2=7

apply additon property of equality

x-2+2=7+2

x=9

6 0
3 years ago
Which expression has a value of 12?<br> A. 3+32<br> B. 32 +23<br> C. (4+2)2<br> D. 42-32
alekssr [168]
The answer is C because if you multiply 4 and 2 by 2 it would become 8 and 4, 8+4=12
4 0
3 years ago
You are given the information that P(A) = 0.30 and P(B) = 0.40.
Ad libitum [116K]

Answer:

1.B. No. You need to know the value of P(A and B). 2.C. Yes P(A and B) =0, so P(A or B) = P(A) + P(B).

Step-by-step explanation:

We can solve this question considering the following:

For two mutually exclusive events:

\\ A_{1}\;and\;A_{2}

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) (1)

An extension of the former expression is:

\\ P(A_{1} or A_{2}) = P(A_{1}) + P(A_{2}) - P(A_{1} and A_{2}) (2)

In <em>mutually exclusive events,</em> P(A and B) = 0, that is, the events are <em>independent </em>one of the other, and we know the probability that <em>both events happen</em> <em>at the same time is zero</em> (P(A <em>and</em> B) = 0). There are some other cases in which if event A happens, event B too, so they are not mutually exclusive because P(A <em>and</em> B) is some number different from zero. Notice the difference between <em>OR</em> and <em>AND. The latter implies that both events happen at the same time.</em>

In other words, notice that the formula (2) provides an extension of formula (1) for those events that are not <em>mutually exclusive</em>, that is, there are some cases in which the events share the same probabilities in a way that these probabilities <em>must be subtracted</em> from the total, so those probabilities in common do not "inflate" the actual probability.

For instance, imagine a person going to a gas station and ask for checking both a tire and lube oil of his/her car. The probability for checking a tire is P(A)=0.16, for checking lube oil is P(B)=0.30, and for both P(A and B) = 0.07.

The number 0.07 represents the probability that <em>both events occur at the same time</em>, so the probability that this person ask for checking a tire or the lube oil of his/her car is:

P(A or B) = 0.16 + 0.30 - 0.07 = 0.39.

That is why we cannot simply add some given probabilities <em>without acknowledging if the events are or not mutually exclusive</em>, whereas we can certainly add the probabilities in question when we know that both probabilities are <em>mutually exclusive</em> since P(A and B) = 0.

In conclusion, knowing the events are mutually exclusive <em>does</em> provide <em>extra information</em> and we can proceed to simply add the probabilities of either event; thus, the answers are those in which <em>we need to previously know the value of P(A and B)</em>.  

7 0
3 years ago
What is the least possible degree of a polynomial that has roots -5, 1 + 4i, and -4i?
just olya [345]
Hello,

Answer D:

the roots are -5,1+4i,1-4i,-4i,4i.

7 0
3 years ago
Read 2 more answers
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