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2 years ago

Use the area of the rectangle to find the area of the triangle.

Mathematics

1 answer:

aivan3 [116]2 years ago

6 0

Answer:

Step-by-step explanation:

the area of the triangle is 20. using the base of the rectangle [5] and the height of the triangle[8]. I did the same for the rectangle and got the area of 40 for the rectangle

I hope this helped :)

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What is the system of linear equations graphed below?

pochemuha

Answer:

It's:

y = $-\frac{1}{2}x + 1$

y = -2x - 4

Hope this helps!

6 0

2 years ago

Read 2 more answers

Please help me with this math question!

Alenkinab [10]

The bases are both 2, so we would subtract the exponents. This is because the rule is

(a^b)/(a^c) = a^(b-c)

In this case,
a = 2
b = 3/4
c = 1/2

So this means
b - c = (3/4) - (1/2) = (3/4) - (2/4) = 1/4

After subtracting the exponents, the final exponent is 1/4

So the expression simplifies to 2^(1/4) which is the same as $\sqrt[4]{2}$ (fourth root of 2)

4 0

2 years ago

let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)

statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

$\sin (\theta)=\frac{3}{5}$

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

$x^2+3^2=5^2$

Solving for x, we have

$\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}$

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

$\tan (y)=\frac{12}{5}$

Describes the following triangle

Using the Pythagorean Theorem again, we have

$5^2+12^2=h^2$

Solving for h, we have

$\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}$

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

$\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}$

To calculate the sine and cosine of the sum

$\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}$

We can use the following identities

$\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}$

Using those identities in our problem, we're going to have

$\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}$

4 0

9 months ago

If u go to sleep at 9:30 p.m. and wake up at 6:30a.m. The next morning how long did u sleep

puteri [66]

Well first do this
12.00 - 9.30 = 2.30
2.30 + 6.30 = 9
You slept 9hrs

8 0

2 years ago

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Write an equation of the line that passes through the given point with the given slope

Inessa05 [86]

Did Yu Ever Find The Answer I got the same question??

8 0

2 years ago