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nikdorinn [45]
3 years ago
12

What is the radius of a circle with an area of 78.5 cubic inches? Use 3.14 for pi. Enter your answer in the box.

Mathematics
2 answers:
Molodets [167]3 years ago
5 0

Answer:


If the area of the circle is 78.5 squared inches (note we use squared inches for areas and cubic inches for volume) and we want to know its radius r, we have to use the formula of the area of the circle:


A_{circle}=\pi r^{2}  


Then isolate r:


r^{2}=\frac{A_{circle}}{\pi}  


Applying square root on both sides:


\sqrt{r^{2}}=\sqrt{\frac{A_{circle}}{\pi}}  


r=\sqrt{\frac{A_{circle}}{\pi}}  


Substituting the known values:


r=\sqrt{\frac{78.5 inch^{2}}{3.14}}  


r=5>>>>>This is the radius

k0ka [10]3 years ago
3 0

Answer:

its basicaly just 5 :)

Step-by-step explanation: i took the test

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mezya [45]

Answer:

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For maximum volume, we find V' = 0

i.e 1440 -480x = 0

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3 years ago
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SOLUTIONS

Solve a given equations or algebraic symbols?

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(A)

\begin{gathered} (f+g)(x)=(x^2+2x)+(1-x^2) \\ collect\text{ like terms} \\ x^2-x^2+2x+1 \\ (f+g)(x^)=2x+1 \end{gathered}

(B)

\begin{gathered} (f-g)(x)=(x^2+2x)-(1-x^2) \\ =x^2+2x-1+x^2 \\ =x^2+x^2+2x-1 \\ (f-g)(x)=2x^2+2x-1 \end{gathered}

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\begin{gathered} fg(x)=(x^2+2x)(1-x^2) \\ =x^2-x^4+2x-2x^3 \\ fg(x)=-x^4-2x^3+x^2+2x \end{gathered}

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\begin{gathered} \frac{f}{g}(x)=(x^2+2x)\div(1-x^2) \\ =\frac{x^2+2x}{1-x^2} \end{gathered}

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Answer:

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Answer:

(11, 12)

Step-by-step explanation:

<u>Mid point coordinates:</u>

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