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Lena [83]
2 years ago
6

A, B and C lie on a straight line.

Mathematics
1 answer:
horsena [70]2 years ago
6 0
Here you go, i added a bit of explanation as to why i used the numbers to help you understand the method :)

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Plzz i need help like rn!!!! plz :(
frozen [14]

Answer:

Step-by-step explanation:

The second choice down is the one you want.  I'm not sure why you're confused if you simply have to graph the 2 functions to see on your calculator where they intersect.  Unless you don't know how to access the change of base function in a TI84...

Hit "alpha" then "window" and 5 will open up the option to enter a base on a log.

8 0
3 years ago
Please answer correctly!! You will be reported if you don't!!
serious [3.7K]

Answer:

QUESTION?

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Divide 29 into two parts so that the sun of the squares of the parts is 425.Find the value of each Part.
Taya2010 [7]

Answer:

13 and 16

Step-by-step explanation:

let the 2 parts be x and y, then

x + y = 29 → (1) and

x² + y² = 425 → (2)

From (1) → x = 29 - y → (3)

substitute x = 29 - y into (2)

(29 - y)² + y² = 425 ( expand factor )

841 - 58y + y² + y² = 425 ( rearrange into standard form )

2y² - 58y + 416 = 0 ← in standard quadratic form

divide all terms by 2

y² - 29y + 208 = 0

Consider the factors of 208 which sum to - 29

These are - 13 and - 16, hence

(y - 13)(y - 16) = 0

equate each factor to zero and solve for y

y - 13 = 0 ⇒ y = 13

y - 16 = 0 ⇒ y = 16

substitute these values into (3)

x = 29 - 13 = 16 and x = 29 - 16 = 13

The 2 parts are 13 and 16


4 0
3 years ago
Read 2 more answers
5*10^9 divided by 5*10^4
tiny-mole [99]
The answer is 1e + 13 i think
5 0
2 years ago
Read 2 more answers
Please help with answers
Artyom0805 [142]
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Any height that is less than 54 does NOT qualify.

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Any weight that's 800 pounds or less is OK.

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. . . . . they're NOT all greater than 21
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. . . . . they ARE all 10 or more .

4).  First, write down the number of cans that
each student collected, but arrange them in order.
Then check each choice.
A).  misses the highest 3 students completely
B).  includes everybody
C).  misses the lowest 3 students completely
D).  OK, but the first and last intervals aren't needed,
       because nobody's cans are in those intervals
3 0
3 years ago
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