How may riders filled 20 cars?

Mathematics

1 answer:

dimulka [17.4K]3 years ago

3 0

20 people one in each car

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Linda is going to rent a truck for one day. There are two companies she can choose from, and they have the following prices. Com

stepan [7]

Answer:

70 miles

Step-by-step explanation:

128-65/.9=m

128-65=63

63/.9=70 miles

70<or equal to m

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2 years ago

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Given g of x equals cube root of the quantity x minus 3, on what interval is the function positive?

zmey [24]

The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

<h3>on what interval is the function positive?</h3>

The function is positive when g(x) > 0.

Then we need to solve:

∛(x - 3) > 0

We can directly remove the cubic root, because it does not affect the sign of the argument, then:

x - 3 > 0

x > 3

The function is positive when x is larger than 3, then the interval in where the function is positive is: (3, ∞)

If you want to learn more about functions:

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2 years ago

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An old house in Pomona, CA is inhabited by a variety of ghosts. Ghost appearances occur in the house according to a Poisson proc

shutvik [7]

Answer:

The probability is 0.503

Step-by-step explanation:

If the ghost appearances occur in the house according to a Poisson process with mean m, the time between appearances follows a exponential distribution with mean 1/m. so, the probability that the next ghost appearance happens before x hours is equal to:

$P(X\leq x)=1-e^{-xm}$

Then, replacing m by 1.4 ghosts per hour we get:

$P(X\leq x)=1-e^{-1.4x}$

Additionally, The exponential distribution have a memoryless property, so if it is now 1:00 p.m. and we want the probability that ghost appear before 1:30 p.m., we need to find the difference in hours from 1:00 p.m and 1:30 p.m. no matter that the last ghost appearance was at 12:35 p.m.

Therefore, there are 0.5 hours between 1:00 p.m. and 1:30 p.m, so the probability that the 7th ghost will appear before 1:30 p.m is calculated as:

$P(x\leq 0.5)=1-e^{-1.4*0.5} =0.503$