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Rus_ich [418]
3 years ago
10

Standard form, degree, leading coefficient of 2x(2)-7x(4)+5x

Mathematics
1 answer:
Drupady [299]3 years ago
8 0
-19x

lmk if this helped
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What is the area of the unshaded region
QveST [7]
Need more info please ?
8 0
3 years ago
Find the diameter and circumference of a circle with the radius of 13.1 km.
Alexandra [31]
R = 13.1
so
<span>diameter  = 13.1 x 2 = 26.2 km
</span>circumference = 2 pi r = 26.2 pi km
or
circumference = 26.2 x 3.14 = 82.27 km
4 0
3 years ago
Use the model to solve for x. A) x = 1 B) x = 3 C) x = 5 D) x =
Novay_Z [31]

Answer:

<h3>            D){?}    x = 7</h3>

Step-by-step explanation:

x + 3•(+1) = 2•x + 4•(-1)

x + 3  =  2x - 4

  -3         -3

 x  =  2x - 7

-2x      -2x

- x  =  -7

÷(-1)     ÷(-1)

  x = 7

7 0
3 years ago
find the x-intercepts and the coordinates of the vertex for the parabola Y equals negative X squared plus 8X -12. If there’s mor
Oksanka [162]

Answer:

x = 2, and 6

x = 2 , 6

Step-by-step explanation:

The quadratic function to analyze is: y = -x^2+8x-12

In order to find where the corresponding parabola intercepts the x axis, we set it equal to zero (y = 0):

y = -x^2+8x-12\\0 = -x^2+8x-12\\x^2-8x+12=0

This equation is easy to solve by factoring. We look for a air of integer numbers whose product equals the constant term "12", and whose combinig renders the coefficient of the middle term of the trinomial "-8".

The two such numbers are "-2" and "-6". We use them to split the middle term, and then solve by factoring by grouping:

x^2-8x+12=0\\x^2-2x-6x+12=0\\(x^2-2x)+(-6x+12)=0\\x(x-2)-6(x-2)=0\\(x-2)(x-6)=0

For the product of two factors to render zero, we need either one to be a zero.This means that (x-2)=0 (that is x = 2), or (x-6)=0 (that is x = 6).

So, there are two x-intercepts: x= 2, and 6

3 0
3 years ago
The image of F(-5,-9) after translating along &lt;4, 6 &gt; and then translating along &lt; 3, 5&gt; is? F’(?,?)
dusya [7]
<h3>Answer:  (2, 2)</h3>

==============================================

Explanation:

The phrasing "translated along <4,6>" is another way of saying "shift 4 to the right, shift 6 up"

In general, "translated along <m,n>" is the same as writing (x,y) \to (x+m, y+n). If m is positive, then we shift m units to the right. If m is negative, then we shift to the left. The same story happens with the n, but we focus on the y coordinate.

-------------

With all that in mind, starting at F(-5,-9) and translating along <4,6> has us arrive at (-1, -3). Add 4 to the x coordinate and add 6 to the y coordinate.

We can say

(x,y) \to (x+4,y+6)\\\\(-5,-9) \to (-5+4,-9+6)\\\\(-5,-9) \to (-1,-3)\\\\

Showing that (-5,-9) moves to (-1,-3)

This is after the first translation, but there's a second translation.

We'll apply the same idea, but different numbers this time

(x,y) \to (x+3,y+5)\\\\(-1,-3) \to (-1+3,-3+5)\\\\(-1,-3) \to (2,2)\\\\

So (-1,-3) moves to (2,2)

Overall we have

  • (-5,-9) move to (-1,-3) after the first translation
  • (-1,-3) move to (2,2) after the second translation

Therefore, the original point ends up at (2,2) which is the final answer

--------------

Extra info:

A nice shortcut is that the vectors <4,6> and <3,5> can be added to get <4+3,6+5> = <7,11>. So overall, we're shifting 7 units to the right and 11 units up when we combine the two translation vectors.

5 0
3 years ago
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