Zeke had 10 marbles in the beginning of the game and he had 7 at the end of the game. What was the percent loss?

Mathematics

1 answer:

zloy xaker [14]3 years ago

3 0

The answer is 30%. It would be like 70% is what you have left of the 100.

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In Mrs. Hu’s classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet, 2/3 have a cat as a pe

tresset_1 [31]

2/3 of the 4/5 of the class has a dog and a cat. Just multiply
(2/3)(4/5)=8/15
45*(8/15)=24

6 0

3 years ago

Read 2 more answers

Please answer question now

Kazeer [188]

Step-by-step explanation:

Here,

diameter(d) of the cylinder is 16 yd.

radius of a cylinder is 16/2 yd= 8 yd.

height (h) of a cylinder is 18yd.

now, we use formula for surface area of cylinder, 

a= 2.pi.r(r+h)

or, a= 2×3.14×8(8+18)

by simplifying it we get, 

The surface area of cylinder is 1306.24 sq.yd.

Hope it helps...

5 0

3 years ago

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1)How many ways can the letters in the word BOOKKEEPER be arranged? (Must show set-up )

sergeinik [125]

Question 1

There are 5 letters (B, O, K, E, R) and there is a total of 10 letters to make up the word.
There are $\frac{10!}{(10-6)!6!}$ ways of arranging the letters, which equal to 210 ways

Question 2

There are seven swimmers in total.
There are $\frac{7!}{(7-1)!1!}$ ways of choosing the first winner, which is 7 ways
There are $\frac{6!}{(6-1)!1!}$ ways of choosing the second winner, which is 6 ways
There are $\frac{5!}{(5-1)!1!}$ ways of choosing the third winner, which is 5 ways
There are 7×6×5=210 ways of choosing first, second, and third winner

Question 3

The probability of eating an orange and a red candy is $\frac{15}{31}$ × $\frac{9}{30}$ , which equals to $\frac{9}{62}$

The probability of eating two green candies is $\frac{7}{31}$ × $\frac{6}{30}$ which equals to $\frac{7}{155}$