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2 years ago

Refering to the equation, tell how

Mathematics

1 answer:

Ugo [173]2 years ago

5 0

Answer:

the scale factor is the vertical expansion factor.

Step-by-step explanation:

The scale factor of 2 in

g(x) = 2·F(x)

means g(x) is a <em>vertical expansion</em> (not shrink) of F(x) — by a factor of 2.

_____

<em>Additional comment</em>

The equation g(x) could be considered to be ...

g(x) = F(x·√2)

in which case g(x) could be interpreted as a <em>horizontal shrink</em> by a factor of (√2)/2. Squeezing a parabola horizontally has the same effect on its appearance as stretching it vertically.

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Zarrin [17]

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Step-by-step explanation:

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3 years ago

In a box there are six envelopes each containing two cards. Three of the envelopes contain two red cards, two of them contain a

Sphinxa [80]

Answer:

$\frac{2}{5}$

Step-by-step explanation:

3 envelopes having 2 red card

2 envelopes having 1 red card and 1 black card

1 envelope having 2 black cards

We are given that . An envelope is selected at random and a card is withdrawn and found to be red.

So, No. of ways of envelope having red card = 3+2 = 5

No. of required ways of envelope having 1 red card and 1 black card = 2

So, probability of getting an envelope having 1 red card and 1 black card = $\frac{2}{5}$

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2 years ago

Select all possible values for x in the equation x^3=375?

Helga [31]

<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

To solve the problem, we need to remember the following properties of the exponents and roots:

$a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}$

Then, we are given the expression:

$x^{3}=375$

So, finding "x", we have:

$x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}$

Hence, the possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

Have a nice day!

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3 years ago