Given:
The volume of a cube-shaped box is 
cubic meter.
To find:
The perimeter of each of its faces.
Solution:
Let "a" be the side length of the cube shaped box. Then the volume of the box is:
It is given that the volume of a cube-shaped box is cubic meter.
Taking cube root on both sides, we get
Now, the perimeter of each face of a cube is:
Where, a is the side length of the cube.
Putting , we get
Therefore, the perimeter of each face of a cube-shaped box is 2 meters.
Answer: D) y= 14/17x - 4/17
Answer:
-4, -6, -3, -5, -1. The inequality solved for n is n ≥ -6.
Step-by-step explanation:
Substitute all the values in the equation.
n/2 ≥ -3
-10/2 ≥ -3
-5 is not ≥ -3.
n/2 ≥ -3
-7/2 ≥ -3
-3.5 is not ≥ -3.
n/2 ≥ -3
-4/2 ≥ -3
-2 is ≥ -3.
n/2 ≥ -3
-9/2 ≥ -3
-4.5 is not ≥ -3.
n/2 ≥ -3
-6/2 ≥ -3
-3 is ≥ -3.
n/2 ≥ -3
-3/2 ≥ -3
-1.5 is ≥ -3.
n/2 ≥ -3
-8/2 ≥ -3
-4 is not ≥ -3.
n/2 ≥ -3
-5/2 ≥ -3
-2.5 is ≥ -3.
n/2 ≥ -3
-2/2 ≥ -3
-1 is ≥ -3.
To solve the inequality n/2 ≥ -3 for n, do these steps.
n/2 ≥ -3
Multiply by 2.
n ≥ -6.
The interior angle measures are 900 degrees
131+122+125+148+107+126 = 759
900-759 =141
X = 141
Solution:
we are given that
In a class, every student knows French or German (or both).
15 students know French, and 17 students know German.
Suppose there are x student who knows both French and German.
Then Total number of student in the class will be 
But to guess the largest possible number of student in the class we can assume x=0
Hence the largest Possible number of Student in the class=32
