From a bag of 5 red and 6 green marbles, a red marble is drawn and NOT 1

Mathematics

1 answer:

atroni [7]2 years ago

7 0

Answer:

Step-by-step explanation:

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A bowl contains 4 red marbles and 3 yellow marbles. Tim randomly draws 3 red marbles from the bowl. He replaces each marble afte

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So,

The probability of drawing a yellow marble is $\frac{3}{7}$ .
Since he replaces the marble after it is drawn out, the probability of drawing another yellow is the same: $\frac{3}{7}$ .

The probability of drawing a red marble is $\frac{4}{7}$ .

In order to get the probability of drawing 2 yellow marbles and 1 red marble, given that each marble is replaced after it is drawn out, we must multiply the fractions together.

$( \frac{3}{7} )( \frac{3}{7} )( \frac{4}{7} ) = \frac{36}{343}$

Because the order of the marbles doesn't matter, we will multiply the probability by 3.
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