ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
Answer:
First equation has extra 6s and this extra 6s=54-42=12
6s=12. s=2
Step-by-step explanation:
6*2+10t=42 ........ 10t=30 t=3
400g=.4kg
.4kg×25p/1kg=10p
Answer:
D
Step-by-step explanation:
the slope is 12/10 which simplifies to 6/5 and the y intercept is 2
