In the coordinate plane, what is the length of the line segment that connects points at (5, 4) and (−3, −1) ?

2 answers:

8 0

To find the length of a line between two points with known x- and y- coordinates, use:
sqrt((change in x)^2 + (change in y)^2),
which I know may look confusing but it isn't really:

sqrt((5 - -3)^2 + (4 - -1)^2)
= sqrt(8^2 + 5^2)
= sqrt(64 + 25)
= sqrt(89)

cluponka [151]3 years ago

8 0

The Answer is 9.43 Hope this helps :D

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(07.05)<br> Graph the first six terms of a sequence where a = -10 and d = 3.

butalik [34]

Answer:

Step-by-step explanation:

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3 years ago

There are 1500 bees in a colony. Each month, the number of bees decreases by 12%. There are 800 flowering plants in a garden. Ea

Shkiper50 [21]

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5 0

3 years ago

Help please

Novosadov [1.4K]

$General\ equation\ for\ line\ in\ slope\ intercept\ form:\\\\y=ax+b\\\\To\ find\ a\ and\ b\ substitude\ points\ (-7,5)\ (-4,1)\ into\ equation\\\\ 
\left \{ {{5=-7a+b}\ \ \ \ \atop {1=-4a+b\ |*-1}} \right.\\\\ \left \{ {{5=-7a+b}\ \ \ \ \atop {-1=4a-b}} \right.\\\\
+----\\\\Addition\ method\\\\
4=-3a\ \ |:(-3)\\\\
a=-\frac{4}{3}\\\\
b=5+7a=5+7*(-\frac{4}{3})=5-\frac{28}{3}=-4\frac{1}{3}\\\
Answer\ y=-\frac{4}{3}x-4\frac{1}{3}\\\\
Checking\ solution:\\
y-5=-\frac{4}{3}(x+7)
$ $y-5=-\frac{4}{3}x-\frac{28}{3}\\\\
y=-\frac{4}{3}x-\frac{28}{3}+5\\\\
y=-\frac{4}{3}x-4\frac{1}{3}\\\\Answer:B \ and\ D.$