6yd
8yd a =48sq yd (6×8=48)
4yd
12yd a=48sq yd (4×12=48)
I believe the answer would be 6/25 simplified. 12/50 would be the original answer
I really need one too. Thanks for the question.
Answers:
<em>How much did the temperature change from Sunday High to Mondays High?</em>
Change = 4 °C
<em>What was the difference between the high temperatures on Friday and Wednesday?</em>
Difference = 10 °C
Explanation:
Taking into account the graph, we get that the high temperature each day is:
Sunday: -10°C
Monday: -6 °C
Tuesday: - 4 °C
Wednesday: -6 °C
Thursday: 0 °C
Friday: 4 °C
Saturday: -2 °C
So, the change from Sunday High to Mondays High can be calculated as:
Change = Monday - Sunday
Change = -6 °C - (- 10 °C)
Change = -6 °C + 10 °C
Change = 4 °C
In the same way, the difference between the high temperatures on Friday and Wednesday can be calculated as:
Difference = Friday - Wednesday
Difference = 4 °C - (-6 °C)
Difference = 4 °C + 6 °C
Difference = 10 °C
Therefore, the answers are:
<em>How much did the temperature change from Sunday High to Mondays High?</em>
Change = 4 °C
<em>What was the difference between the high temperatures on Friday and Wednesday?</em>
Difference = 10 °C
Find <span>tan<span>(<span><span>5π</span>12</span>)</span></span> and sin ((5pi)/12)
Answer: <span>±<span>(2±<span>√3</span>)</span>and±<span><span>√<span>2+<span>√3</span></span></span>2</span></span>
Explanation:
Call tan ((5pi/12) = t.
Use trig identity: <span><span>tan2</span>a=<span><span>2<span>tana</span></span><span>1−<span><span>tan2</span>a</span></span></span></span>
<span><span>tan<span>(<span><span>10π</span>12</span>)</span></span>=<span>tan<span>(<span><span>5π</span>6</span>)</span></span>=−<span>1<span>√3</span></span>=<span><span>2t</span><span>1−<span>t2</span></span></span></span>
<span><span>t2</span>−2<span>√3</span>t−1=0</span>
<span>D=<span>d2</span>=<span>b2</span>−4ac=12+4=16</span>--> <span>d=±4</span>
<span>t=<span>tan<span>(<span><span>5π</span>12</span>)</span></span>=<span><span>2<span>√3</span></span>2</span>±<span>42</span>=2±<span>√3</span></span>
Call <span><span>sin<span>(<span><span>5π</span>12</span>)</span></span>=<span>siny</span></span>
Use trig identity: <span><span>cos2</span>a=1−2<span><span>sin2</span>a</span></span>
<span><span>cos<span>(<span><span>10π</span>12</span>)</span></span>=<span>cos<span>(<span><span>5π</span>6</span>)</span></span>=<span><span>−<span>√3</span></span>2</span>=1−2<span><span>sin2</span>y</span></span>
<span><span><span>sin2</span>y</span>=<span><span>2+<span>√3</span></span>4</span></span>
<span><span>siny</span>=<span>sin<span>(<span><span>5π</span>12</span>)</span></span>=±<span><span><span>√<span>2+<span>√3</span></span></span>2</span></span></span>
