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maria [59]
3 years ago
6

12g+6=78 thats what i need help with

Mathematics
2 answers:
Mrrafil [7]3 years ago
4 0
I assume you need to solve for g?
12g + 6 = 78
- 6
12g = 72
÷ 12
g = 6
I hope this helps! Let me know if you want me to explain anything :)
BabaBlast [244]3 years ago
3 0
First take 6 away from 78
78-6= 72
Then divide 72 by 12
72/12 = 6
So g = 6
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(x^2 + 5x + 4) : 2

Step-by-step explanation:

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Please help i will give brainily for the first correct answer
jeka94

Step-by-step explanation:

Draw picture of 2 points (-1, 7), (1, 5) at line x and y

and use the formula

slope = (y2 - y1)/(x2 - x1)

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If convexity to the left slope -

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3 years ago
Write the equation y=-3x+3 in function notation using f(x) to denote the function.
Mumz [18]

The function notation form of the given equation; y = -3x +3 as in the task content is; f(x) = -3(x) +3.

<h3>What is the function notation form of the equation?</h3>

According to the task content, the equation given; y = -3x +3 is to be written in function notation.

Consequently, since the function expression given is linear in variable X, it follows that the required function notation is;

f(x) = -3x +3.

Read more on function notation;

brainly.com/question/25638609

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5 0
2 years ago
A financial talk show host claims to have a 55.3 % success rate in his investment recommendations. You collect some data over th
baherus [9]

Answer:

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

Step-by-step explanation:

For each recommendation, there are only two possible outcomes. Either it was a success, or it was a failure. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

p = 0.553, n = 10

If the claim is correct and the performance of recommendations is independent, what is the probability that you would have observed 4 or fewer successful:

This is

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.553)^{0}.(0.447)^{10} = 0.0003

P(X = 1) = C_{10,1}.(0.553)^{1}.(0.447)^{9} = 0.0039

P(X = 2) = C_{10,2}.(0.553)^{2}.(0.447)^{8} = 0.0219

P(X = 3) = C_{10,3}.(0.553)^{3}.(0.447)^{7} = 0.0724

P(X = 4) = C_{10,4}.(0.553)^{4}.(0.447)^{6} = 0.1567

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0003 + 0.0039 + 0.0219 + 0.0724 + 0.1567 = 0.2552

There is a 25.52% probability of observating 4 our fewer succesful recommendations.

3 0
3 years ago
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