<span>toggle your tracking on or off</span>
Answer and Explanation:
Given data:
Distance (D) = 40 KM
Speed of light in the fiber =Distance/ speed of light in the fiber
a) Delay (P) = Distance/ speed of light in the fiber
= (40,000 Meters/2×108 m/s)
=( 40×103 Meters/2×108 m/s)
Propagation delay (P) = 0.0002 seconds or 200 microseconds
b)
if propagation delay is 0.0002 Seconds roundup trip time (RTT) will be 0.0004 Seconds or 400 micro Seconds
Essentially since transmission times and returning ACKs are insignificant all we really need is a value slightly greater than 0.0004 seconds for our timeout value.
c)
The obvious reasons would be if the data frame was lost, or if the ACK was lost. Other possibilities include extremely slow processing on the receive side (late ACK).
Or Extremely Slow Processing of the ACK after it is received back at the send side.
Answer: A block-level element is any element that starts a new line.
Answer:
Monday Video: 5.4.20 Section 18.5
Work due: 18.5 Worksheet
CW
Tuesday Video: 5.5.20 Section 18.6
Work due: 18.6 Worksheet
HW
Wednesday Video: 5.6.20 Section 18.7
Work due: 18.7 Classwork
CW
Thursday Video: 5.7.20 Section 18.7
Work due: 18.7 Homework
HW
Friday Video: 5.8.20 Section 18.5-18.7
Work due: Textbook page 615 #5-19 (not #13)
HWaccuracy
Explanation:
