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nasty-shy [4]
2 years ago
15

Enthusiasm codehs 7.6.4 Write a function called add_enthusiasm that takes a string and returns that string in all uppercase with

an exclamation point added.
Computers and Technology
1 answer:
daser333 [38]2 years ago
3 0

Answer:

Hope this help

Explanation:

def add_enthusiasm(string):

   return string.upper() + "!"

   

print add_enthusiasm("hello")

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To quit, a user types 'q'. To continue, a user types any other key. Which expression evaluates to true if a user should continue
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Answer:

!(key == 'q')

Explanation:

Based on the description, the coded expression that would equate to this would be

!(key == 'q')

This piece of code basically states that "if key pressed is not equal to q", this is because the ! symbol represents "not" in programming. Meaning that whatever value the comparison outputs, it is swapped for the opposite. In this case, the user would press anything other than 'q' to continue, this would make the expression output False, but the ! operator makes it output True instead.

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Write down eight points on how modern technology have effected our life ?
luda_lava [24]

Answer:

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3 years ago
You also learn in class that one kilobyte of computer memory will hold about 2/3 of a page of typical text (without formatting).
Travka [436]

Answer:

The flashdrive can hold 35389 400-pages-books

Explanation:

If \frac{2}{3} of a page occupies 1 kB of memory, we can calculate how much memory a book will take

2/3kB=1 page\\ x kB=400 pages\\266.67 kB=400 pages

Now that we know that a book average file size is about 266,67 kB, we calculate how many of them can a 9 GB flash drive hold.

To do the calculation, we have to know how many kilobytes are in 9 gigabytes.

There is 1024 kilobytes in a megabyte, and 1024 megabytes in a gigabyte, so:

Memory_{in _kilobytes}^{} =1024\frac{kilobytes}{megabytes} *1024\frac{megabytes}{gigabytes}*9=9437184 kilobytes

Finally, knowing the average file size of a book and how much memory in kilobytes the 9 GB flash drive holds, we calculate how many books can it hold.

Books=\frac{Flash drive memory}{Filesize of a book} =\frac{9437184kilobytes}{266.67\frac{kilobytes}{book} } =35389,4 books

The flashdrive can hold 35389 400-pages-books, or 14155776 pages of typical text.

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