Question

I need help on #2 please help me fast

Answer 1

$\frac{3ab^{2} - d^{3}}{a}$

$\frac{3(-\frac{1}{2})(4)^{2} - (-3)^{3}}{-\frac{1}{2}}$

$\frac{3(-\frac{1}{2})(16) + 27}{-\frac{1}{2}}$

$\frac{3(-8) + 27}{-\frac{1}{2}}$

The answer is B.

$\frac{-24 + 27}{-\frac{1}{2}}$

$\frac{3}{-\frac{1}{2}}$

$-6$