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GarryVolchara [31]
3 years ago
7

I need help on #2 please help me fast

Mathematics
1 answer:
Marrrta [24]3 years ago
4 0

\frac{3ab^{2} - d^{3}}{a}

\frac{3(-\frac{1}{2})(4)^{2} - (-3)^{3}}{-\frac{1}{2}}

\frac{3(-\frac{1}{2})(16) + 27}{-\frac{1}{2}}

\frac{3(-8) + 27}{-\frac{1}{2}}

The answer is B.

\frac{-24 + 27}{-\frac{1}{2}}

\frac{3}{-\frac{1}{2}}

-6

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malfutka [58]
Add y to both sides then do the algebra
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Solve the following systems of equations algebraically. Write your answer in the form of (x, y).
Ne4ueva [31]

Let's solve your system by substitution.
y
=
3
x
+
5
;
y
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Step: Solve
y
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+
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for y:
y
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3
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Step: Substitute
3
x
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5
for
y
in
y
=
x
+
19
:
y
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x
+
19
3
x
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5
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x
+
19
3
x
+
5
+
−
x
=
x
+
19
+
−
x
(Add -x to both sides)
2
x
+
5
=
19
2
x
+
5
+
−
5
=
19
+
−
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(Add -5 to both sides)
2
x
=
14
2
x
2
=
14
2
(Divide both sides by 2)
x
=
7

Step: Substitute
7
for
x
in
y
=
3
x
+
5
:
y
=
3
x
+
5
y
=
(
3
)
(
7
)
+
5
y
=
26
(Simplify both sides of the equation)

Answer:
x
=
7
and
y
=
26
8 0
3 years ago
Plz answer correctly I don’t wanna fail plz answer!!!!!not much!!!!!!!
Triss [41]
I’m pretty sure yes it is
6 0
3 years ago
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Ghella [55]
There are a total of 20 snacks in each bag.  We consider the probability of picking a bag of peanuts with reduced sodium and then a granola bar with reduced sodium, then multiply by 2 (because we could pick them in the other order).

There is a 5/20 chance of picking a sodium-reduced bag of peanuts first, and a 2/20 chance of picking a sodium-reduced granola bar next.  Thus, the chance of picking them together in that order is 5/20*2/20=10/400, or 1/40.  Because we could pick the snacks in either order, we multiply by two, for a result of a 1/20 probability.
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4 years ago
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I believe it's 179f = 223
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5 0
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