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3 years ago

The area of the triangle is 24 square feet. what is the length of the base?

Mathematics

1 answer:

Lubov Fominskaja [6]3 years ago

8 0

Answer:

16 feet

Step-by-step explanation:

Area of a Triangle: (Base*Height)/2.

Therefore, Base:(2A)/Height =(2*24)/2=16

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How many solutions does the system of equations below have? (PLEASE HELP)

Artist 52 [7]

Answer:

y= -54-2

y= -56 &

x= -54/ -9

x= 6

Step-by-step explanation:

y= -9x-2

-9x= y+2 divide bothe side by -9

x=y+2/-9

y= -9(y+2/ -9) -2 = (y+2)-2

y= -2(y+2)

y= -2y-4

y+2y= -4

3y= -4 divide bothe side by 3

y= -4/3

x=y+2/ -9

x= -4/3+2/-9

x= -2/3× -9

x=18/3

x=6

6 0

3 years ago

Question 2 <><><><><><><><><><><>

drek231 [11]

Answer:

I deserve brainliest just as all good boys deserves fudgeeeeee

Step-by-step explanation:

v^2 = 25/81

v= the square root of 25/81 = 5/9

since that isn't a choise, don't simplify.

D works too because negative x negative = positive

CCCCCCC

4 0

3 years ago

Read 2 more answers

a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you

aniked [119]

Answer:

0.64 = 64% probability that the student passes both subjects.

0.86 = 86% probability that the student passes at least one of the two subjects

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Passing subject A

Event B: Passing subject B

The probability of passing subject A is 0.8.

This means that $P(A) = 0.8$

If you have passed subject A, the probability of passing subject B is 0.8.

This means that $P(B|A) = 0.8$

Find the probability that the student passes both subjects?

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)P(A) = 0.8*0.8 = 0.64$

0.64 = 64% probability that the student passes both subjects.

Find the probability that the student passes at least one of the two subjects

This is:

$p = P(A) + P(B) - P(A \cap B)$

Considering $P(B) = 0.7$ , we have that:

$p = P(A) + P(B) - P(A \cap B) = 0.8 + 0.7 - 0.64 = 0.86$

0.86 = 86% probability that the student passes at least one of the two subjects

3 0

3 years ago

Pls help ASAP, will give barinliest

garik1379 [7]

Answer:

Step-by-step explanation:

im to lazy but subtract 180 and the others are equal just compare small angles to big ones and should equal 180

6 0

3 years ago

Read 2 more answers

-18 = -6n - 6 + 2n Solve for n.

vodomira [7]

Answer:

n = 3

Step-by-step explanation:

-18 = -6n - 6 + 2n

-18 = -6n +2n -6 (Combine like terms)

-18= -4n -6

-18+6= -4n -6+6 (Addition Property of Equality)

-12 = -4n

-12/-4 = -4n/-4 (Division Property of Equality)

3=n

The value of 'n' is 3.

3 0

3 years ago