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3 years ago

Jamie bought two puzzles for $5.00 and three puzzles for $7.50. Write and solve an equation to find the cost of 15 puzzles

Mathematics

1 answer:

gladu [14]3 years ago

3 0

2x=$5.00
x=$2.50
3x=$7.50
x=$2.50
15x=
15(2.50)=$37.50
hope this helps!

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astraxan [27]

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3 years ago

A fluid moves through a tube of length 1 meter and radius r=0.006±0.00025 meters under a pressure p=4⋅105±2000 pascals, at a rat

iris [78.8K]

Answer:

Maximum error for viscosity is 17.14%

Step-by-step explanation:

We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

$n = (\frac{\pi}{8}) (\frac{pr^4}{v})\\$

The implicit derivative with respect to the time would be

$\frac{dn}{dt} = \frac{\pi}{8} ( \frac{r^4}{v} \frac{dp}{dt} + \frac{4pr^3}{v}\frac{dr}{dt} )$

If we multiply everything by dt we get

$dn = \frac{\pi}{8} ( \frac{r^4}{v} dp + \frac{4pr^3}{v} dr})$

Remember that the error is given by $\frac{dn}{n}$ therefore doing some algebra we get that

$\frac{dn}{n} = 4 \frac{dr}{r} + \frac{dp}{p}$

Since, r = 0.006 , dr = 0.00025 , p = 4*105 , dp = 2000 we get that

$\frac{dn}{n} = 0.1714$

Which means that the maximum error for viscosity is 17.14%.

5 0

3 years ago

1. How are pounds per gallon and kilograms per liter alike? How are they different?

Goryan [66]

Answer:

1)= 1 kilogram per liter (kg/l) + 8.35 pound per gallon (lb/gal)

2)= 4.4704 meters per seconds

3)= 12in= 1ft ratio is 12:1

4)= 1ft=12in ratio is 1:12

5)= 3ft= 1 yard ratio is 3:1

6)=1 yard = 3ft ratio 1:3

Step-by-step explanation:

12 in = 1 foot

1 yard = 3 feet

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I hope this helps

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3 years ago

Estimate 195 divided by 4. Tell which method is used.

ki77a [65]

195 ÷ 4 = 48.75
Is this what you wanted?

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3 years ago

Read 2 more answers

Solve for x. Show your work.

puteri [66]

So, these are actually pretty simple once you learn the equality used to solve for "x" and when to implement this method. You can use this equality to solve for a segment "x" anytime that two secant lines cutting through a circle come from the same point outside the circle.

Secant: by geometric definition is just a straight line that cuts a curve into multiple pieces.

I did one of them for you hopefully you can use my work for "a" to help you solve for "b". For a. I got x=7.

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3 years ago