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3 years ago

Which of the following is the solution to the inequality below?

Mathematics

1 answer:

garik1379 [7]3 years ago

7 0

The answer is C. x>-3/35

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Elijah put 2x+3 dollars in the bank the first week. The following week he doubled the first week’s savings and put that amount i

ella [17]

I believe the answer would be $79.50.

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3 years ago

B-1.6=(0.4) to the second power. SHOW WORK

olya-2409 [2.1K]

First, do 0.4 + 0.4. So, you can see what number you should get when you check your answer. For this, you should get 0.8

Then, do 0.8 + 1.6
After you add those 0.8 and 1.6, you should get your answer.
To check your answer, plug in your answer where B is and see if you get 0.8. I hope this helps! I did as much explaining as I could! If you need anymore help with this, just comment

4 0

3 years ago

The radius of a circle is (7x+3)cm. Write an expression to represent the area of the circle in simplified form

zepelin [54]

Answer:

A = π(7x + 3)² cm²

Step-by-step explanation:

A = πr² is the appropriate equation. If r = 7x + 3 cm, then the area of this particular circle is:

A = π(7x + 3)² cm²

3 0

3 years ago

Compare and contrast perpendicular bisected and altitude

elena55 [62]

A perpendicular bisector forms two right angles and splits the line in two equal parts.

The altitude does create two right angles, but doesn't have to create two equal parts.

6 0

3 years ago

Use induction to prove that 2? ?? for any integer n>0 . Indicate type of induction used.

Hoochie [10]

Answer with explanation:

The given statement is which we have to prove by the principal of Mathematical Induction

$2^{n}>n$

1.→For, n=1

L H S =2

R H S=1

2>1

L H S> R H S

So,the Statement is true for , n=1.

2.⇒Let the statement is true for, n=k.

$2^{k}>k$

---------------------------------------(1)

3⇒Now, we will prove that the mathematical statement is true for, n=k+1.

$\rightarrow 2^{k+1}>k+1\\\\L H S=\rightarrow 2^{k+1}=2^{k}\times 2\\\\\text{Using 1}\\\\2^{k}>k\\\\\text{Multiplying both sides by 2}\\\\2^{k+1}>2k\\\\As, 2 k=k+k,\text{Which will be always greater than }k+1.\\\\\rightarrow 2 k>k+1\\\\\rightarrow2^{k+1}>k+1$

Hence it is true for, n=k+1.

So,we have proved the statement with the help of mathematical Induction, which is

$2^{k}>k$

3 0

3 years ago