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brilliants [131]
3 years ago
7

Aman borrowed $ 3000 from a bank for 3 months . A friend was cosigner of the man's personal note . The bank collected 3 1 2 \% s

imple interest on the date of maturity a ) How much did the man pay for the use of the money ? b Determine the amount he repaid to the bank on the due date of the note .
Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

Answer:3500

Step-by-step explanation:

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Determine which transformation took place from f(x) to g(x).
Fantom [35]

Answer:

mali aaudina so sorry and again please don't asked me

7 0
3 years ago
Let f ( x , y )=5 x and let C be the segment of the parabola y = 2 x squared joining O( 0 , 0 ) and P( 1 , 2 ). a. Find a parame
taurus [48]

a. We can parameterize C by

x=t

y=2t^2

with 0\le t\le1. Then

\displaystyle\int_C5x\,\mathrm dS=\int_0^15t\sqrt{1+16t^2}\,\mathrm dt=\dfrac5{48}(17^{3/2}-1)

b. We can parameterize the opposite direction by instead setting

x=1-t

y=2(1-t)^2

with 0\le t\le 1. Then

\displaystyle\int_C5x\,\mathrm dS=\int_0^15(1-t)\sqrt{1+16(1-t)^2}\,\mathrm dt=-\int_1^05u\sqrt{1+16u^2}\,\mathrm dt=\int_0^15u\sqrt{1+16u^2}\,\mathrm du

which gives the same value as in part (a).

5 0
3 years ago
The equation of the line passing through (2, 3) with a slope of 5 is y = []x- [] ​
Katen [24]

Answer:    y = 5x - 7

Step-by-step explanation:

y = mx + b, where m = slope

We plug in the point, where x = 2, and y = 3

y = 5x - b

3 = 5(2) - b

3 = 10 - b

b + 3 = 10

b = 7

y = 5x - 7

4 0
3 years ago
Out of 1,100 discs tested, 13 are defective. Estimate the number of defective discs in a batch of 41,000.
frosja888 [35]
This is a simple proportion

1100 : 13 = 41000 : x

For every 1100 discs, 13 are defective, meaning that there will be an X number for each 41000

13 * 41000 = 1100 * x

13 * 410 = 11 * x
5330 = 11 * x
x = 5330/11
x = 484.5

That means that for every 41000, approximately 485 discs will break down.
5 0
3 years ago
Read 2 more answers
NEED HELP ON NUMBER 13 AND 14
Kazeer [188]

Answer:

Question 13: For age groups y=1 and y=1.3 response is 8 microseconds.

Question 14: The club was making a loss between 11.28 and 4.88 years.

Step-by-step explanation:

Question 13:

The age group y for which the response rate R is 8 microseconds  is given by the solution of the equation

8=y^4 +2y^3 - 4y^2 -5y +14.

We graph this equation and find the solutions to be

y=1;   y=1.302;     y=-2;    y=-2.302.

Since only positive solutions for y are valid in the real world we take only those.

Thus only for age groups y=1 and y=1.3 the response is 8 microseconds.

Question 14:

The footbal club is making a loss when p(t)

Or

t^3 -14t^2 +20t +120

We graph this inequality and find the solutions to be

t and 4.88

Since in the real world only positive values for t are valid, we take the the second solution to be true.

Thus the club was making a loss in years 4.88

5 0
4 years ago
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