Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

Answer: $22.80/hour
Step-by-step explanation: 364.80 : 16 = 22.80
Answer:
1/3
Step-by-step explanation:
volume of a cylinder = nr^2h
Volume of a cone = 1/3(nr^2h)
n = 22/7
r = radius
h = height
If the volume of a cylinder is 300, the volume of a cone = 1/3 x 300 = 100
the capacity of a cone is 1/3 that of a cylinder