You measure a rectangle that the length is 3 inches and the width is

Can you help me simplify this and explain it -----------------------------------------------------------------------------------

Archy [21]

A. Factor 28 + 7g 7(g <span>+ 4)

add
28 </span><span>+ 7g

= 7 (g </span>+ 4)

B. (12r + 15) – 65 Remove parentheses
12r+15-65

= 12r - 50

C. 24 – (8p – 12)

24 - (8p - 12) = -8p + 36

24 - (8p - 12) -(8p - 12) 8p + 12

= 24-8p+12

Simplify 24-8p+12

Group like terms
-8p+12+24

Add the numbers 12+24=36

Answer is -8p+36

7 0

3 years ago

5 yd<br> 3 yd<br> 4.8 yd<br> 28 yd<br> 8 yd

kompoz [17]

Answer:

i am converting to meters

Step-by-step explanation:

5 yd =4.572 meters

3yd=2.7432 meters

4.8yd=2.7432 meters

28yd=25.6032 meters

8yd=7.3152 meters

5 0

3 years ago

a cookie factory uses 1/6 pf a barrel pf oatmeal in each batch of cookies, the factory used 1 1/3 barrels of oatmeal yesterday.

miv72 [106K]

Answer:

5 batches

Step-by-step explanation:

1/6 oatmeal can make 1 batch, so 5/6 makes 5 batches

8 0

2 years ago

The first 5 multiples of 18 after 0 are?

ololo11 [35]

Answer:

18,36,54,72,90 are first five multiples of 18

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :

$\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ$ .

3 0

2 years ago