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san4es73 [151]
3 years ago
15

seventy percent of the students applying to a university are accepted. using the binomial probability function, what is the prob

ability that among the next 10 applicants exactly 1 will be rejected? Determine the expected number of acceptances? Compute the standard deviation?

Mathematics
1 answer:
liq [111]3 years ago
4 0
Check the attached file for the solution.

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Wah..I need to ask my bro to answer this.. Brb
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If <img src="https://tex.z-dn.net/?f=x%3D2z" id="TexFormula1" title="x=2z" alt="x=2z" align="absmiddle" class="latex-formula">,
Readme [11.4K]

Answer:

x = 1

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Step-by-step explanation:

z = 3/y

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Read 2 more answers
Find the product of (x + 5)(x − 5).
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Answer:

x² - 30 + 5x

Step-by-step explanation:

(x + 5)(x − 5)

=x(x − 5)+5(x − 5)

=x² - 5 + 5x - 25

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2 years ago
A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec
VMariaS [17]

Answer:

19.1-3.355\frac{1.5}{\sqrt{9}}=17.42    

19.1+3.355\frac{1.5}{\sqrt{9}}=20.78    

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=19.1 represent the sample mean

\mu population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=9-1=8

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that t_{\alpha/2}=

Now we have everything in order to replace into formula (1):

19.1-3.355\frac{1.5}{\sqrt{9}}=17.42    

19.1+3.355\frac{1.5}{\sqrt{9}}=20.78    

And the best option would be:

C. [17.42,20.78]

5 0
3 years ago
Do even numbers have more factors in odd numbers or do i numbers have more factors than even numbers
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<span>It is because even numbers always have a factor of two, and therefore, larger composite even numbers will have factors of two and other even numbers based around two, such as 4, 8, 16, 32, and so on. On the other hand, numbers which are odd can have factors of 3, 5, and 7 for example, and their numbers based around them(3, 9, 27; 5, 10, 15; 7, 49, 343; and so on). If we look into it, notice how for odd numbers the space between the numbers based around 3, 5, and 7 are increasingly further apart. This is the reason why less large odd integers to have numerous factors. It is because odd numbers cannot have the prime factor 2, this will reduce their factor number. And is is also because even numbers are already divided by 2, this will give them more factors over the odd numbers.</span>
4 0
3 years ago
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