64 hours per hour average
350 miles ÷5.25 hours in which it took= 63.63 rounded is 64 mph average
Answer:
3 30 page printers, 10 70 page printers
Step-by-step explanation:
x + y = 13
40x+70y = 820
Solving for y in first equation gives: y = 13 - x
Plug into second equation: 40x + 70(13 - x) = 820
40x + 910 - 70x = 820
-30 x = -90
x = 3
Plug into original equation: 3 + y = 13
y must = 10.
So, the company owns 3 thirty page presses, and 10 70 page presses,
The number of miles for which the car has been driven if one paid $122.50 as in the task content is; 2.5 miles.
<h3>For how many miles was the car driven?</h3>
It follows from the task content that the total amount paid was; $122.50.
Hence, after subtraction the constant charges, for the day and for gas, the remainder is;
$122.50 - $50 - $35
= $37.50.
Ultimately, if the charge per mile is $15, then the number of miles driven is; $37.50/$15
= 2.5 miles.
Read more on cost per unit;
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Answer:
This is a <u>Sample Response</u> for the question,"Write four to six sentences describing Momma or Mrs. Flowers. In your analysis, include at least two personality traits of the person. Support your ideas about the individual’s personality traits with evidence from the text."
Your welcome :)
(a) Average time to get to school
Average time (minutes) = Summation of the two means = mean time to walk to bus stop + mean time for the bust to get to school = 8+20 = 28 minutes
(b) Standard deviation of the whole trip to school
Standard deviation for the whole trip = Sqrt (Summation of variances)
Variance = Standard deviation ^2
Therefore,
Standard deviation for the whole trip = Sqrt (2^2+4^2) = Sqrt (20) = 4.47 minutes
(c) Probability that it will take more than 30 minutes to get to school
P(x>30) = 1-P(x=30)
Z(x=30) = (mean-30)/SD = (28-30)/4.47 ≈ -0.45
Now, P(x=30) = P(Z=-0.45) = 0.3264
Therefore,
P(X>30) = 1-P(X=30) = 1-0.3264 = 0.6736 = 67.36%
With actual average time to walk to the bus stop being 10 minutes;
(d) Average time to get to school
Actual average time to get to school = 10+20 = 30 minutes
(e) Standard deviation to get to school
Actual standard deviation = Previous standard deviation = 4.47 minutes. This is due to the fact that there are no changes with individual standard deviations.
(f) Probability that it will take more than 30 minutes to get to school
Z(x=30) = (mean - 30)/Sd = (30-30)/4.47 = 0/4.47 = 0
From Z table, P(x=30) = 0.5
And therefore, P(x>30) = 1- P(X=30) = 1- P(Z=0.0) = 1-0.5 = 0.5 = 50%
