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Lynna [10]
2 years ago
9

You rented a car on vacation to go sightseeing for a day. You had to pay $50 for the day and $.15 per mile, along with $35 for g

as. If you paid $122.50, how many miles did you drive?
Mathematics
1 answer:
stellarik [79]2 years ago
3 0

The number of miles for which the car has been driven if one paid $122.50 as in the task content is; 2.5 miles.

<h3>For how many miles was the car driven?</h3>

It follows from the task content that the total amount paid was; $122.50.

Hence, after subtraction the constant charges, for the day and for gas, the remainder is;

$122.50 - $50 - $35

= $37.50.

Ultimately, if the charge per mile is $15, then the number of miles driven is; $37.50/$15

= 2.5 miles.

Read more on cost per unit;

brainly.com/question/19493296

#SPJ1

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example

6,2 reflected over the x axis.

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Y axis rule example

-2,7 reflected over the y axis

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Step-by-step explanation:

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3 years ago
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E is the midpoint of Df, DE=2x+4, and EF=3x-1. Find all segment lengths
sertanlavr [38]
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6 0
3 years ago
Try the numbers 22, 23, 24, 25 in the equation 4/3 = 32/d to test whether any of them is a solution. a. 23 is a solution. c. 24
S_A_V [24]

Answer:

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Step-by-step explanation:

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In order to test the given number for the solution, we will plugin each number in the unknown variable d and see if it satisfies the equation.

1) d=22

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Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 2}{22\div 2}

\frac{4}{3}=\frac{16}{11}

The above statement can never be true and hence 22 is not a solution.

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The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

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Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 8}{24\div 8}

\frac{4}{3}=\frac{4}{3}

The above statement is always true and hence 24 is a solution.

4) d=25

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The fractions can no further be reduced.

The statement can never be true and hence 25 is not a solution.

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