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Lynna [10]
2 years ago
9

You rented a car on vacation to go sightseeing for a day. You had to pay $50 for the day and $.15 per mile, along with $35 for g

as. If you paid $122.50, how many miles did you drive?
Mathematics
1 answer:
stellarik [79]2 years ago
3 0

The number of miles for which the car has been driven if one paid $122.50 as in the task content is; 2.5 miles.

<h3>For how many miles was the car driven?</h3>

It follows from the task content that the total amount paid was; $122.50.

Hence, after subtraction the constant charges, for the day and for gas, the remainder is;

$122.50 - $50 - $35

= $37.50.

Ultimately, if the charge per mile is $15, then the number of miles driven is; $37.50/$15

= 2.5 miles.

Read more on cost per unit;

brainly.com/question/19493296

#SPJ1

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\large\underline{\sf{Solution-}}

Given that,

<em>In triangle ABC</em>

\purple{\rm :\longmapsto\:\angle A + \angle B = 125 \degree \: -  -  - (1) }

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We know,

Sum of all interior angles of a triangle is supplementary.

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\purple{\rm :\longmapsto\:\angle A + \angle B + \angle B + \angle C = 125\degree  + 150 \degree \:}

\purple{\rm :\longmapsto\:\angle A + \angle B + \angle C + \angle B = 275\degree \:}

\purple{\rm :\longmapsto\:180\degree + \angle B = 275\degree \:}

\purple{\rm :\longmapsto\:\angle B = 275\degree - 180\degree  \:}

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On substituting the value in equation (1) and (2), we get

\purple{\rm :\longmapsto\:\angle A + 95\degree  = 125\degree }

\purple{\rm :\longmapsto\:\angle A =  125\degree - 95\degree  }

\purple{\rm :\longmapsto\:\angle A =  30\degree  }

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\purple{\rm :\longmapsto\:95\degree  + \angle C = 150\degree }

\purple{\rm :\longmapsto\:\angle C = 150\degree  - 95\degree }

\purple{\rm :\longmapsto\:\angle C = 55\degree }

Hence,

\begin{gathered}\begin{gathered}\bf\: \rm\implies \:\begin{cases} &\sf{\angle A = 30\degree }  \\ \\ &\sf{\angle B = 95\degree } \\ \\ &\sf{\angle C = 55\degree } \end{cases}\end{gathered}\end{gathered}

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