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bezimeni [28]
3 years ago
10

Help..

Mathematics
1 answer:
timofeeve [1]3 years ago
8 0

Answer:

1. 44

2. 73

Step-by-step explanation:

1:

1/2 (7) (4) + 6 (5) =

1/2 (28) + 30 =

14 + 30 =

44

2:

12 (6) + 1/4 (2^2) =

72 + 1/4 (4) =

72 + 1 =

73

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What is the measurement shown ?
Elodia [21]

answers:

3.5

2.875

about 3.0625

Use thing below for answers

7 0
3 years ago
A study of 10 different weight loss programs involved 500 subjects. Each of the 10 programs had 50 subjects in it. The subjects
Yakvenalex [24]

Answer:

a) (iii) ANOVA

b) The ANOVA test is more powerful than the t test when we want to compare group of means.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

If we assume that we have p=10 groups and on each group from j=1,\dots,p=10 we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2

And we have this property

SST=SS_{between}+SS_{within}

Solution to the problem

Part a

(i) confidence interval

False since the confidence interval work just when we have just on parameter of interest, but for this case we have more than 1.

(ii) t-test

Can be a possibility but is not the best method since every time that we conduct a t-test we have a chance that we commit a Type I error.

(iii) ANOVA

This one is the best method when we want to compare more than 1 group of means.

(iv) Chi square

False for this case we don't want to analyze independence or goodness of fit, so this one is not the correct test.

Part b

The ANOVA test is more powerful than the t test when we want to compare  group of means.

8 0
4 years ago
Please help me with number 19 a and b
kondor19780726 [428]
A.
The second and first quadrant, because the hour and temperatures are unlikely to be negative numbers. All positive numbers for both X and Y values are in the second quadrant. If the hour is before noon, then the X value will venture into quadrant one. The diagram shows the quadrants in a graph.

B. For both the time and the temperature to be negative, and in quadrant four, you would have to be located in possibly Alaska or northern Canada. In such locations colder areas would be more likely to have negative temperatures and at times before 12.

6 0
4 years ago
A recipe includes 2 cups of flour and two thirds
Aloiza [94]

Answer:

3:1

Step-by-step explanation:

Flour : butter milk

2: 2/3

6:2

3:1

8 0
3 years ago
If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.
nordsb [41]

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)}  ^2  = {det (adjacent of A)} ^2

 

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2  = {det(A)  ^3−1 }^2

 

=(11)^2×2  = 11^4

 =146.41

5 0
3 years ago
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