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3 years ago

11

you have $63.50. you earn additional money by raking leaves. you purchase a sweatshirt $44.99 and you have $53.51 left. how much

money did you earn raking leafs?

1 answer:

Contact [7]3 years ago

4 0

$93.50 is the answer

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What is the area of the trapezoid?<br> 68<br> 54<br> 76<br> 108

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108 is the answer for this question

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Write an equation in point slope form for the given line

PtichkaEL [24]

Answer:

$\large\boxed{y-4=-\dfrac{1}{2}(x-1)}$

Step-by-step explanation:

Look at the picture.

The formula of a slope:

The point-slope form of an equation of a linear function:

$y-y_1=m(x-x_1)$

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have two points (1, 4) and (-3, 6). Substitute:

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3 years ago

If the product of any two rational numbers is 2 and one of them is 1/7, find the other number.

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Answer:

The other number is 14.

Step-by-step explanation:

To find the other number, all you have to do is divide 1/7 by 2.

$\frac{2}{1/7}$

$= 2 \cdot 7$

$= 14$

Hope this helped!

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3 years ago

Which expression is equivalent to -1/2(-3/2x+6x+1)-3

stira [4]

Answer:

$-\frac{9}{4}x-\frac{7}{2}$

Step-by-step explanation:

We want to find an expression that is equivalent to $-\frac{1}{2}(-\frac{3}{2}x+6x+1)-3$ .

Since we can;t get the options, we simplify the given expression.

The reason is that, the given expression will be equivalent to the simplified one.

We combine similar terms to get:

$-\frac{1}{2}(\frac{9}{2}x+1)-3$

We now expand to get:

$-\frac{1}{2}*\frac{9}{2}x-\frac{1}{2}-3$

We perform the subtraction of the last two terms to get:

$-\frac{1}{2}*\frac{9}{2}x-\frac{7}{2}$

We now multiply to get:

$-\frac{9}{4}x-\frac{7}{2}$

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3 years ago

Test yourself 2

mafiozo [28]

Ok, so dy/dx=0 at the point (0,3) that is where x=0 and y=3.

$\int { 6x+6dx } \\ \\ =\frac { 6{ x }^{ 2 } }{ 2 } +6x+C\\ \\ =3{ x }^{ 2 }+6x+C$

$\\ \\ \therefore \quad { f }^{ ' }\left( x \right) =3{ x }^{ 2 }+6x+C$

Now, f'(x)=0 when x=0.

Therefore:

$0=C\\ \\ \therefore \quad { f }^{ ' }\left( x \right) =3{ x }^{ 2 }+6x$

Now:

$\int { 3{ x }^{ 2 } } +6xdx\\ \\ =\frac { 3{ x }^{ 3 } }{ 3 } +\frac { 6x^{ 2 } }{ 2 } +C$

$={ x }^{ 3 }+3{ x }^{ 2 }+C\\ \\ \therefore \quad f\left( x \right) ={ x }^{ 3 }+3{ x }^{ 2 }+C$

But when x=0, y=3, therefore:

$3=C\\ \\ \therefore \quad f\left( x \right) ={ x }^{ 3 }+3{ x }^{ 2 }+3$

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3 years ago

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