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3 years ago

If the value of third order determinant is 11. Then what is the value of the determinant formed by its cofactors.

Mathematics

1 answer:

nordsb [41]3 years ago

5 0

Answer:

146.41

Step-by-step explanation:

third order determinant = determinant of 3×3 matrix A

given ∣A∣=11

det (cofactor matrix of A) =set (transpare of cofactor amtrix of A) (transpare does not change the det)

=det(adjacent of A)

{det (cofactor matrix of A)} ^2 = {det (adjacent of A)} ^2

(Using for an n×n det (cofactor matrix of A)=det (A)^n−1 )

we get

det (cofactor matrix of A)^2 = {det(A) ^3−1 }^2

=(11)^2×2 = 11^4

=146.41

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Answer: Option C

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Step-by-step explanation:

If the lines m and n are parallel then the large triangle and the small triangle are similar triangles, because they have equal angles.

By definition for similar triangles it is satisfied that if they have sides of length a, b, c and a', b', c' then:

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In this case

$a = 12\\a' = 4\\c = 15\\c' = y$

So:

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Now solve the equation for the variable y

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Then

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Finally the answer is:

$y=5$ , $x=10$

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3 years ago

Help!! Please im having trouble

bekas [8.4K]

Answer:

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Step-by-step explanation: All you have to do is divide the numerator by the denominator to make it into a decimal. For instance....

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Step-by-step explanation:

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3 years ago

Read 2 more answers

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sattari [20]

Answer:

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Step-by-step explanation:

when a line is tangent to a circle, it is perpendicular to the line from the center of the circle to the intersection of the line and the circle. so first we are going to find the slope of the line in the circle.

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