100/x=300/45 Factor out 100/x=15×20/15×3 Cancel common factor
100/x=20/3 100(3)=20(x) 300=20x 300/20=X 15=x
<span>Take the integral:
integral (cos(x))/sqrt(cos(x)+1) dx
For the integrand (cos(x))/sqrt(1+cos(x)), substitute u = 1+cos(x) and du = -sin(x) dx:
= integral (u-1)/(sqrt(2-u) u) du
For the integrand (-1+u)/(sqrt(2-u) u), substitute s = sqrt(2-u) and ds = -1/(2 sqrt(2-u)) du:
= integral -(2 (1-s^2))/(2-s^2) ds
Factor out constants:
= -2 integral (1-s^2)/(2-s^2) ds
For the integrand (1-s^2)/(2-s^2), cancel common terms in the numerator and denominator:
= -2 integral (s^2-1)/(s^2-2) ds
For the integrand (-1+s^2)/(-2+s^2), do long division:
= -2 integral (1/(s^2-2)+1) ds
Integrate the sum term by term:
= -2 integral 1/(s^2-2) ds-2 integral 1 ds
Factor -2 from the denominator:
= -2 integral -1/(2 (1-s^2/2)) ds-2 integral 1 ds
Factor out constants:
= integral 1/(1-s^2/2) ds-2 integral 1 ds
For the integrand 1/(1-s^2/2), substitute p = s/sqrt(2) and dp = 1/sqrt(2) ds:
= sqrt(2) integral 1/(1-p^2) dp-2 integral 1 ds
The integral of 1/(1-p^2) is tanh^(-1)(p):
= sqrt(2) tanh^(-1)(p)-2 integral 1 ds
The integral of 1 is s:
= sqrt(2) tanh^(-1)(p)-2 s+constant
Substitute back for p = s/sqrt(2):
= sqrt(2) tanh^(-1)(s/sqrt(2))-2 s+constant
Substitute back for s = sqrt(2-u):
= sqrt(2) tanh^(-1)(sqrt(1-u/2))-2 sqrt(2-u)+constant
Substitute back for u = 1+cos(x):
= sqrt(2) tanh^(-1)(sqrt(sin^2(x/2)))-2 sqrt(1-cos(x))+constant
Factor the answer a different way:
= sqrt(1-cos(x)) (csc(x/2) tanh^(-1)(sin(x/2))-2)+constant
Which is equivalent for restricted x values to:
Answer: |
| = (2 cos(x/2) (2 sin(x/2)+log(cos(x/4)-sin(x/4))-log(sin(x/4)+cos(x/4))))/sqrt(cos(x)+1)+constant</span>
Answer:
20 < x < 38.
Step-by-step explanation:
An obtuse angle has a value between 90 and 180.
90 < 5x - 10 < 180
5x - 10 > 90
5x > 100.
x > 20.
5x - 10< 180
5x < 190
x < 38
The experimental probability of each event is as follows:
- Landing open side up = 1/50 = 0.02 = 2%.
- Landing closed side up = 5/50 = 1/10 = 0.1 = 10%.
- Landing on its side = 44/50 = 0.88 = 88%.
The experimental probability of an event is the ratio of the number of outcomes that favored the event to the total number of outcomes in the experiment.
In the question, we are given that Jake tossed a paper cup 50 times and recorded the position how it landed, which is shown in the table:
Open-sided up: 1
Closed side up 5
On the side: 44.
We are asked to determine the experimental probability of each outcome.
The number of outcomes, when the landing is open-sided up is 1.
The number of outcomes, when the landing is closed-sided up is 5.
The number of outcomes, when the landing is on the side up is 44.
The total number of times the experiment took place is 50.
Thus, the experimental probability of each event is as follows:
- Landing open side up = 1/50 = 0.02 = 2%.
- Landing closed side up = 5/50 = 1/10 = 0.1 = 10%.
- Landing on its side = 44/50 = 0.88 = 88%.
Learn more about the experimental probability at
brainly.com/question/24298250
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17)
x² + 8 = -8
x² = -8 - 8
x² = 16
x = ±√-16
x = ±√16i
x = <span>±4i
</span>
18)
x² + 5 = -3
x² = -3 - 5
x² = -8
x = ±√-8
x = ±√8i
x = ±2√2i
19)
x² + 3 = 0
x² = -3
x = ±√-3
x = <span>±</span>√3i
hope this helps, God bless!
