The 50th term in the sequence is 199
Arithmetic sequence
The nth term of an arithmetic sequence is expressed as:
Tn = a+ (n - 1)d
where:
- a is the first term
- n is the number of terms
- d is the common difference
The sequence formed by the amount of Whatchamacallits produced as;
3, 7, 11, 15...
a = 3
d = 11-7 = 7-3 = 4
Substitute
Tn = 3 + (n-1) * 4
Tn = 3 + 4n -4
Tn = 4n - 1
Hence the explicit formula that models the production for the nth term of the sequence is Tn = 4n - 1
If n = 50
T50 = 4(50) - 1
T50 = 199
Hence the 50th term in the sequence is 199
Learn more on sequence here; brainly.com/question/6561461
Answer:
four multipled by one plus three multiplied by one tenth plus 9 multiple by one one thousandth
Kilo means 1000
a meter is 1/1000 of a kilometer so 1 meter=0.001 kilometer
Answer:
x = 57.2
Step-by-step explanation:
Equation:
32.8 + x = 90
x = 90 - 32.8
x = 57.2
Answer:
Step-by-step explanation: