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cupoosta [38]
3 years ago
9

It is recommended that adults get 8 hours of sleep each night. A researcher hypothesized college students got less than the reco

mmended number of hours of sleep each​ night, on average. The researcher randomly sampled 20 college students and found no evidence to reject the null hypothesis at the​ 5% significance level. What is true regarding the​ p-value from this hypothesis​ test?
Mathematics
1 answer:
yanalaym [24]3 years ago
5 0

Answer:

Given:

Sample size, n = 20

Significance level = 5% = 0.05

Mean, u = 8

Here, the sample mean was not given.

Here the null and alternative hypothesis will be:

H0 : u = 8

H1 : u < 8

In this case, since there is no evidence to reject the null hypothesis, H0, at 0.05 level of significance, we can say that the p-value is greater than the level of significance, 0.05.

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Brian was scuba diving at the Great Barrier Reef in Australia. After he jumped in the water, he descended 18 feet. Then he rose
Levart [38]

amswer:

-13 feet

step by step:

-18+5=-13

8 0
2 years ago
Five grams of sugar are added to a 40-gram serving of a breakfast cereal that is 10% sugar. What is the percent concentration of
tamaranim1 [39]
10g+0.10(40g)=14 grams of sugar.
7 0
3 years ago
(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x

\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x

\cot^2 x = \cot^2 x


8 0
3 years ago
At the Hula Factory, the assembly line produces 212 leis in a batch. The leis are packaged in boxes with 30 each. If 14 batches
nikklg [1K]

Answer:

197 leis left over

Step-by-step explanation:

14 times 212 = 2968

2968/30 = 98.93

212 times 0.93 = 197

98 packages and 197 leis left over

7 0
2 years ago
Calculate the average rate of change of f(x) = 1 x - x2 - 2 for 3 ≤ x ≤ 6. A) -163 18 B) -18 163 C) 163 18 D) 18 163
larisa86 [58]
To solve this we are going to use the average rate of change formula: A(x)= \frac{f(b)-f(a)}{b-a}
where
A(x) is the average rate of change of the function
f(a) is the position function evaluated at a
f(b) is the position function evaluated at b
a is the first point in the interval
b is the second point in the interval

We can infer for our problem that the first point is 3 and the second point is 6, so a=3 and b=6. Lets replace those values in our formula:
A(x)= \frac{f(b)-f(a)}{b-a}
A(x)= \frac{f(6)-f(3)}{6-3}
A(x)= \frac{6-6^2-2-(3-3^2-2)}{3}
A(x)= \frac{-32-(-8)}{3}
A(x)= \frac{-32+8}{3}
A(x)= \frac{-24}{3}
A(x)=-8

We can conclude that the average rate of change of the function f(x) = 1 x - x2 - 2 for <span>3 ≤ x ≤ 6 is -8</span>
3 0
3 years ago
Read 2 more answers
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