Question

A recent study reported that 22% of adults in France admitted to texting or e-mailing while driving. A random sample of 110 French adults was randomly selected. What is the probability that 26 or more of these adults admitted to admitted to texting or e-mailing while driving?

Answer 1

Answer:

Step-by-step explanation:

ported that 22% of adults in France admitted to texting or e-mailing while driving. A random sample of 110 French adults was randomly selected. What is the probability that 26

Using a binomial distribution with mean = n*p = 110*0.22 = 24.2 and variance = n*p*(1-p) = 24.2*(1-0.22) = 18.876

Approximating it to a normal distribution,

$P(x\geq 26)\\\\=P(Z\geq \frac{26-24.2}{\sqrt{18.876} } )\\\\=P(Z\geq 0.41)\\\\=0.3481$