Answer:
Speed of one dog is 2.5 m/s and other dog is 5.5 m/s.
Step-by-step explanation:
Total distance between the two dogs = 360 m
Let the speed of one dog be x m/s, then the speed of second dog will be x+3 m/s.
Then total speed of two dogs = x+x+3 = 2x+3
Times = 20 seconds
After 20 seconds, distance left between them = 200 m
Distance traveled by the two dogs in 20 seconds = 360 m - 200 m
= 160 m
We know, Speed = 
2x+3 = 
2x = 8-3 = 5
x = 2.5 m/s
Speed of first dog = 2.5 m/s
Speed of second dog = x+3 = 2.5 +3
= 5.5m/s
Speed of one dog is 2.5 m/s and other dog is 5.5 m/s.
Answer:
y = x +3
Step-by-step explanation:
The equation of a parallel line can use the same x- and y-coefficients as the given equation. Only the constant needs to be found to make the line go through the given point.
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<h3>form of the solution</h3>
The equation of the given line is ...
y = x +4
So, the equation of a parallel line will be ...
y = x +b . . . . . for some y-intercept b
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<h3>solution</h3>
Using the given point (x, y) = (-1, 2), we can fill in the values and solve for b.
2 = -1 +b
3 = b . . . . . . add 1 to both sides
The desired equation is ...
y = x +3
Answer:
b^20/a^12
Step-by-step explanation:
b to the power of 20 over a to the power of 12
72.3 - 39.1 = 4 tens - 7 ones - 2 tens is the correct order after rewriting.
Given the formula 72.3 + (-39.1)
removing the parentheses:
= 72.3 + (-39.1) (-39.1)
= 72.3 - 39.1
converting decimal numbers to place values
72.3 = 7tens plus 2units plus 3tenths
72.3 = 7(10) (10)
+2(1)+3(1/10)
72.3 =70+2+0.3
Similarly, 39.1
39.1 = 3tens plus 9units plus 1tenth
39.1 = 3(10)+9(1)+1(1/10)
39.1 =30+9+0.1
72.3 - 39.1 = 70+2+0.3 - (30+9+0.1)
72.3 - 39.1 = 70+2+0.3 - 30-9-0.1
72.3 - 39.1 = 70-30+2-9+0.3-0.1
72.3 - 39.1 = 40 - 7 +0.2
Hence after rewriting we get 72.3 - 39.1 = 4 tens - 7 ones - 2 tens
Learn more about mathematical expressions at
brainly.com/question/17178740
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Answer: I think it would be 80 feet I hole I’m correct.
Step-by-step explanation: So to explain 20 + 50 is 80 and that’s how I got the answer I am not 100% sure but I wanted to help you :-)
