Each prize is worth 3 tickets at the game center.How many tickets are needed for 23 prizes?

Mathematics

2 answers:

Zolol [24]3 years ago

5 0

3 tickets = 1 price

3 * 23 =69

69 tickets = 23 prizes

Soloha48 [4]3 years ago

3 0

Answer:

Step-by-step explanation: ok so 45 +? So the answer would be 34 because you found the missing number

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Genuinely confused, how would you solve this? (will mark for brainliest!!)

Yanka [14]

Answer:

Length of the bold sector: 40.3ft

Area of the bold sector: 282.08

Step-by-step explanation:

Finding the sector length: Assuming that pi=3.14, the diameter is 87.92 ft. The ratio of the bold section to the whole circumference is 165 to 360. So you need to multiply the circumference by the ratio. (87.92 x 165)/360=40.3

Finding the sector area: Assuming that pi=3.14, the area of the circle is 615.44 sq. ft. The ratio of the sector area to the area of the whole circle is 165:360. (615.44 x 165)/360=282.08, rounded to the nearest 100th.

3 0

3 years ago

In a survey, the planning value for the population proportion is p* = 0.35. How large a sample should be taken to provide a 95%

lions [1.4K]

Answer:

$n=\frac{0.35(1-0.35)}{(\frac{0.05}{1.96})^2}=349.59$

And rounded up we have that n=350

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p$ represent the real population proportion of interest

$\aht p$ represent the estimated proportion for the sample

n is the sample size required (variable of interest)

$z$ represent the critical value for the margin of error

Solution to the problem

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: